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iogann1982 [59]
3 years ago
9

Does O2 have a single, double, or triple bond?

Chemistry
1 answer:
miss Akunina [59]3 years ago
4 0
Answer: has a double bond
Explanation: O2 has a double bond in its normal form. That is O=O. There are no unpaired electrons in this case are there since there are 2 lone pairs on each oxygen.
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When the gases dihydrogen monosulfide and oxygen react, they form the gases sulfur dioxide and water vapor. Write the balanced c
Anna35 [415]
2(H2S) + 3(O2) -> 2(SO2) + 2(H2O)
7 0
3 years ago
A compound with molecular formula C6H15N exhibits a singlet at d 0.9 ppm (1H), a triplet at 1.10 ppm (3H), a singlet at 1.15 ppm
Triss [41]

Answer:

CH3 - CH2 - NH - C(CH3)3

Explanation:

The 1HNMR is the acronym for Proton nuclear magnetic resonance and it is used in chemistry or Chemical laboratory for the analysis and identification of compounds.

In order to be able to answer the question accurately you have to have the tables containing all the values for chemical shift. The Chemical shift is measured in ppm and it occur due to Resonance frequency variation.

From the table, a singlet at 1.15 ppm (9H) is - C(CH3)3.

A singlet at d 0.9 ppm (1H) shows the presence of a secondary amine group, that is -R2NH group.

A triplet at 1.10 ppm (3H) shows that we have;

CH3- CH2-

A quartet at 2.6 ppm (2H) shows that we have;

-CH2 - CH3.

Therefore, joining all together we have;

CH3 - CH2 - NH - C(CH3)3.

Kindly check attached file for the picture of the structure.

5 0
3 years ago
What is the density of a 6 g of pure copper with a volume of 12 mL?
Sati [7]

Answer:

The density of copper is 0.5 g/mL

Explanation:

Given data:

Mass of copper = 6 g

Volume of copper = 12 mL

Density of copper = ?

Solution:

Formula:

d = m/v

d = density

m = mass

v = volume

d = 6 g/ 12 mL

d = 0.5 g/mL

Thus, the density of copper is 0.5 g/mL

5 0
3 years ago
Questions on maths mechanics
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Answer:

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3 0
4 years ago
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Option B. <span>Rb2O + Cu(C2H3O2)2 → 2RbC2H3O2 + CuO is the correct answer. HOPE IT HELPS</span>
8 0
3 years ago
Read 2 more answers
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