Answer: from the Zn anode to the Cu cathode
Justification:
1) The reaction given is: Zn(s) + Cu₂⁺ (aq) -> Zn²⁺ (aq) +Cu(s)
2) From that, you can see the Zn(s) is losing electrons, since it is being oxidized (from 0 to 2⁺), while Cu²⁺, is gaining electrons, since it is being reduced (from 2⁺ to 0).
3) Then, you can already tell that electrons go from Zn to Cu.
4) The plate where oxidation occurs is called anode, and the plate where reduction occus is called cathode.
So you get that the electrons flow from the anode (Zn) to the cathode (Cu).
Always oxidation occurs at the anode, and reduction occurs at the cathode.
Answer:
Electrical conductivity
Explanation:
Electrical conductivity - A material's ability to conduct electricity
Answer is in the photo. I can only upload it to a file hosting service. link below!
linkcutter.ga/gyko
Answer:
3189.07Pa
Explanation:
The conversion of 23.92mmH to Pa can be achieved in the following way:
760mmHg = 101325Pa
23.92mmHg = (23.92x101325)/760 = 3189.07Pa
