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Kryger [21]
3 years ago
15

PLSSSSS HELPPPPPPP ASAPPPPPP!!!! I WILLL GIVE BRAINLIEST!!!!

Mathematics
1 answer:
Leona [35]3 years ago
4 0

Answer:

A and D represent linear functions

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Brainliest for the correct answer
KiRa [710]
I'm guessing it's 5% lol
6 0
3 years ago
A rectangular garden is 2 feet longer than it is wide. If the width is doubled, 50 extra feet of fencing will be needed to keep
cestrela7 [59]

Answer:

The dimensions of the original garden is 27\times25\ ft.

Step-by-step explanation:

Let the width of the rectangular garden be 'x'.

Now given:

A rectangular garden is 2 feet longer than it is wide.

so we can say that;

Length of the rectangle = (x+2) \ ft

Now to fence the garden we need to find the perimeter of the garden.

Now Perimeter of the garden is equal to twice the sum of the length times width.

framing in equation form we get;

Perimeter of the rectangle = 2(x+x+2)=2(2x+2)=4x+4

Now given:

If the width is doubled, 50 extra feet of fencing will be needed

It  means that Perimeter of the doubled width rectangle is equal to perimeter of original garden plus 50.

framing in equation form we get;

2(2x+x+2)=4x+4+50\\\\2(3x+2)=4x+50

Now Applying distributive property we get;

2\times3x+2\times2=4x+54\\\\6x+4=4x+54

Combining the like terms we get;

6x-4x=54-4\\\\2x=50

Dividing both side by 2 we get;

\frac{2x}{2}=\frac{50}{2}\\\\x=25 \ ft

Length of the rectangular garden = x+2=25+2=27\ ft

Hence the dimensions of the original garden is 27\times25\ ft.

8 0
3 years ago
What is the answer for -6.3x-4.2
jek_recluse [69]

Answer: 26.46

Step-by-step explanation:

7 0
3 years ago
Members of a community garden grow 500 vegetable plant
IRISSAK [1]

Answer:

342 sprouts are planted outside.

Step-by-step explanation:

500 sprouts

500*0.10=50

500-50=450

450*0.20=90

450-90=360

360*0.05=18

360-18=342

7 0
3 years ago
Four married couples have reserved eight seats in a row at the theater. If they arrange themselves​ randomly, what is the probab
gizmo_the_mogwai [7]

The required probability is 2.86%.

Step-by-step explanation:  

The number of ways in which eight persons can sit within themselves at the reserved eight seats is given by

N=8!.

And, the number of ways in which 4 couples (8 persons) can sit such that all the women will sit in adjacent seats and all the men will sit in adjacent​ seats is given by

n=4!\times4!\times2!.

Therefore, the probability that all the women will sit in adjacent seats and all the men will sit in adjacent​ seats is

p=\dfrac{n}{N}=\dfrac{4!\times4!\times2!}{8!}=\dfrac{4\times3\times2\times1\times4!\times2\times1}{8\times7\times6\times5\times4!}=\dfrac{1}{35}=2.86\%.

Thus, the required probability is 2.86%.

4 0
3 years ago
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