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Neporo4naja [7]
2 years ago
14

Let the random variable X be the number of rooms in a randomly chosen owner-occupied housing unit in a certain city. Here are th

e distributions of the number of rooms for owner-occupied units and renter-occupied units:
Rooms 1 2 3 4 5
Owned 0.003 0.002 0.023 0.105 0.218
Rented 0.008 0.027 0.287 0.362 0.165
Rooms 6 7 8 9 10
Owned 0.225 0.198 0.149 0.053 0.024
Rented 0.095 0.033 0.013 0.003 0.004

Required:
a. Express "the unit has 7 or more rooms" in terms of X. x≥7. What is the probability of this event?
b. Express the event {X > 7} in words.
c. What important fact about discrete random variables does comparing your answers to (a) and (b) illustrate?
Mathematics
1 answer:
Vesnalui [34]2 years ago
8 0

Answer:

Part a:

"The unit has 7 or more rooms" in terms of X is given by the unit which has 7, 8, 9 or 10 rooms.

P{ X≥7}= 0.424

Part b:

The event {X > 7} in words is that the unit has more  than 7 rooms. .

Part C:

A continuous random variable  is given by intervals of numbers

A discrete random variable is the variable that is obtained by counting.

Step-by-step explanation:

Part a:

"The unit has 7 or more rooms" in terms of X is given by

{ X≥7} = {x=7} + {x=8} + {x=9} + {x=10}

the unit which has 7, 8, 9 or 10 rooms.

The probability of this event is given by

P{ X≥7} =P {x=7} + P {x=8} + P {x=9} + P {x=10}

P{ X≥7} = 0.198 + 0.149+ 0.053 + 0.024

P{ X≥7}= 0.424

Part b:

The event {X > 7} in words is that the unit has more  than 7 rooms. This does not include the unit having 7 rooms.

Part C:

A continuous random variable takes all the values in the given interval as in part a.The random variable X takes the values between 7 and 10 inclusive of 7.

A discrete random variable is the variable that is obtained by counting as in part b. The variable X takes the values of the units with 8 , 9 or 10 rooms.

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The College Board provided comparisons of Scholastic Aptitude Test (SAT) scores based on the highest level of education attained
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Answer:

a. H_{0}: u1≤u2

H_{a} :u1>u2

b P<0.05   rejected H

Step-by-step explanation:

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The mean is the average . the sum of number over the number of observation

x1=525

x2=487

s.d1=59.42

s.d2=51.74

n1=16

n2=12\alpha =0.05

Determine the hypothesis

H_{0}: u1≤u2

H_{a} :u1>u2

find the degree of freedom(\frac{s1^2}{n1} +\frac{s2^2}{n2} )^2/(\frac{s1^2}{n1} )^2/n1-1+(s2^2/n2)^2/n2-1\\\\(\frac{59.42^2}{16} +\frac{51.7476^2}{12} )^2/(\frac{59.42^2}{16} )^2/16-1+(51.74^2/12)^2/12-1

25

p-value is the probability of obtaining the value of the test statistics. In the column of t-value in the row df=25

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if the P value is actually less than or the same as the significant level, then the null hypothesis is rejected

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2 years ago
Alex invests $2,000 in a company's stock. After a year, the value of Alex's stock has increased to $2,500. What rate of return h
Kay [80]

The rate of interest is 25%

<u>Explanation:</u>

Given:

Principal, P = $2,000

Amount, A = $2500

Time, t = 1 year

Rate of Interest, r = ?

We know:

Amount = P(1+\frac{r}{100})^t

On substituting the value we get:

2500 = 2000 (1 + \frac{r}{100})^1\\ \\\frac{25}{20}= (1+\frac{r}{100})\\

\frac{5}{20} = \frac{r}{100}\\  \\r = \frac{100 X 5}{20} \\\\r = 25

Therefore, the rate of interest is 25%

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3 years ago
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