<span>Answer:
Its too long to write here, so I will just state what I did.
I let P=(2ap,ap^2) and Q=(2aq,aq^2)
But x-coordinates of P and Q differ by (2a)
So P=(2ap,ap^2) BUT Q=(2ap - 2a, aq^2)
So Q=(2a(p-1), aq^2)
which means, 2aq = 2a(p-1)
therefore, q=p-1
then I subbed that value of q in aq^2
so Q=(2a(p-1), a(p-1)^2)
and P=(2ap,ap^2)
Using these two values, I found the midpoint which was:
M=( a(2p-1), [a(2p^2 - 2p + 1)]/2 )
then x = a(2p-1)
rearranging to make p the subject
p= (x+a)/2a</span>
Answer:
do R-P-R-S-P-P-R-P
Step-by-step explanation:
Expression with parenthesis: = 2 ( l + w)
Expression without parenthesis = 2l + 2w
The property we used is known as "Distributive Property"
Let, width = w
Length = w + 70
Perimeter would be: P = 2(w+70+w)
p = 2(2w+70)
p = 4w + 140
Hope this helps!
2 2/5=12:5
5 1/5= 26:5
12:26:5
I think.
Answer:
Unique
Step-by-step explanation:
