Ask question

Ask question

All categories

3 years ago

14

Angle ABC is a right angle. Write and solve an equation to determine the value of the variable, x. Then determine the measures o

f ∠ABD and ∠DBC. SHOW ALL WORK *

2 answers:

Nookie1986 [14]3 years ago

6 0

You are told that the triangle is a right triangle so you know that the angle ABC is 90 degrees. From there you can say that the edition of both expressions will be equal to 90. You use this information to create an equation as the one I showed and solve for x using distributive property, combining like terms, opposite operations and commutative property. Once you have the value of x you can substitute into each expression to find out the measurement of ABD and DBC

Gnesinka [82]3 years ago

6 0

Answer:

3(x+8) + 2x -4

3x +24+ 2x -4

3x+2x+24-4

5x+20

5x +20=90

5x=90-20

5x=70

5x/5= 70/5

x=14

<ABD= 66°

3(14+8)

3× 22

=66

<DBC= 24°

2(14)-4

2×14-4

28-4

=24

You might be interested in

The length of a rectangle is 4 times its width and the perimeter is 150

grandymaker [24]

Answer:

Y = W = 15 ft.

X= L = 60 ft.

So width is 15 and the length is 60.

6 0

3 years ago

Read 2 more answers

Angle D has what measurement according to the protractor?

Aliun [14]

Answer:

B. $90^o$

Step-by-step explanation:

We have been given a protractor and we are asked to find the measure of angle D.

We can see from our given protractor that the measure of angle D is 90 degrees as the ray OD crosses our protractor at 90 degrees.

Therefore, the measure of angle D is 90 degrees and option B is the correct choice.

6 0

3 years ago

What is the reciprocal of 10/11

Svetlanka [38]

Answer:

ιт ιѕ 11/10

Step-by-step explanation:

αℓℓ υ ∂σ ιѕ fℓιρ тнє fяα¢тισи ιѕ αяσυи∂ αи∂ тнєяє уα gσ

нσρє ι ¢συℓ∂ нєℓρ уσυ συт тσ∂αу!!!!!!!!

8 0

3 years ago

Find the value of x in the triangle shown below.

ZanzabumX [31]

Answer:

Step-by-step explanation:

try using each answer choise to find your answer it shoud equal 180 because all of the triangles equal that.

7 0

3 years ago

Consider the equation below. f(x) = 2x3 + 3x2 − 336x (a) Find the interval on which f is increasing. (Enter your answer in inter

Vaselesa [24]

We have been given a function $f(x)=2x^3+3x^2-336x$ . We are asked to find the interval on which function is increasing and decreasing.

(a). First of all, we will find the critical points of function by equating derivative with 0.

$f'(x)=2(3)x^{2}+3(2)x^1-336$

$f'(x)=6x^{2}+6x-336$

$6x^{2}+6x-336=0$

$x^{2}+x-56=0$

$x^{2}+8x-7x-56=0$

$(x+8)-7(x+8)=0$

$(x+8)(x-7)=0$

$x=-8,x=7$

So $x=-8,7$ are critical points and these will divide our function in 3 intervals $(-\infty,-8)U(-8,7)U(7,\infty)$ .

Now we will find derivative over each interval as:

$f'(x)=(x+8)(x-7)$

$f'(-9)=(-9+8)(-9-7)=(-1)(-16)=16$

Since $f'(9)>0$ , therefore, function is increasing on interval $(-\infty,-8)$ .

$f'(x)=(x+8)(x-7)$

$f'(1)=(1+8)(1-7)=(9)(-6)=-54$

Since $f'(1)$ , therefore, function is decreasing on interval $(-8,7)$ .

Let us check for the derivative at $x=8$ .

$f'(x)=(x+8)(x-7)$

$f'(8)=(8+8)(8-7)=(16)(1)=16$

Since $f'(8)>0$ , therefore, function is increasing on interval $(7,\infty)$ .

(b) Since $x=-8,7$ are critical points, so these will be either a maximum or minimum.

Let us find values of f(x) on these two points.

$f(-8)=2(-8)^3+3(-8)^2-336(-8)$

$f(-8)=1856$

$f(7)=2(7)^3+3(7)^2-336(7)$

$f(7)=-1519$

Therefore, $(-8,1856)$ is a local maximum and $(7,-1519)$ is a local minimum.

(c) To find inflection points, we need to check where 2nd derivative is equal to 0.

Let us find 2nd derivative.

$f''(x)=6(2)x^{1}+6$

$f''(x)=12x+6$

$12x+6=0$

$12x=-6$

$\frac{12x}{12}=-\frac{6}{12}$

$x=-\frac{1}{2}$

Therefore, $x=-\frac{1}{2}$ is an inflection point of given function.

3 0

3 years ago