Answer:
The correct option is;
Jason's statement is correct. RST is the same orientation, shape, and size as ABC
Step-by-step explanation:
Here we have
ABC = (2, 1), (3, 3), (4, 1)
RST = (-4, -2), (-3, 0), (-2, -2)
Therefore the length of the sides are as follows
AB = 
AC = 
BC = 
For triangle SRT we have
RS = 
RT = 
ST = 
Therefore their dimensions are equal
However the side with length 2 occurs between (2, 1) and (4, 1) in triangle ABC and between (-4, -2) and (-2, -2) in triangle RST
That is Jason's statement is correct. RST is the same orientation, shape, and size as ABC.