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Vlad1618 [11]
3 years ago
5

Can’t solve this question help plz?

Mathematics
1 answer:
bearhunter [10]3 years ago
7 0
A. 6 51
B. 6 42
C. 34 minutes
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Answer:

The jar has 32 dimes and 18 quarters

Step-by-step explanation:

<u>To solve this problem we can create a system of linear equations in terms of two-variables (say </u>x<u> and </u>y<u>) and solve it.</u> To begin let us analyze the problem further. We know that the values of each coin type are:

Dimes ( x )     = $0.10

Quarters( y )  = $0.25

Total Value   = $7.70

Total Coins   = 50

Now let us set up our system of equations as:

0.10x+0.25y=7.70      Eqn.(1)

x+y=50                     Eqn.(2)

Lets take Eqn.(2) and rerrange it to solve for x as:

x=50-y                     Eqn.(3)

Now lets plug this, in Eqn.(1) so we get the value of y as:

0.10(50-y)+0.25y=7.70\\\\5-0.10y+0.25y=7.70\\\\-0.10y+0.25y=7.70-5\\\\0.15y=2.7\\\\

y=\frac{2.70}{0.15} \\\\y=18

Plugging in y=18 back in Eqn.(3) we finally have:

x=50-18\\x=32

Thus we conclude that in the jar the coins are:

Dimes ( x ) =32

Quarters( y ) =18

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