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2 years ago

Which function is graphed ?

Mathematics

1 answer:

DochEvi [55]2 years ago

3 0

Answer:

its b :) then can i help you

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If x^2 = 50, what is the value of x?

SIZIF [17.4K]

X^2 = 50

Square both sides

x= √50

x= (√25)(√2)

x = 5√2

Final answer: x = 5√2 and since x is to the power of 2 you can have x = + or - x = 5√2

5 0

3 years ago

Read 2 more answers

Solve this equation ×(2)-8×+7=0 Solve the equation

yKpoI14uk [10]

Answer:

-7/6

Step-by-step explanation:

2x-8x+7=0

combine like terms

6x+7=0

subtract the 7 from both sides

6x=-7

divide 6 from both sides

-7/6 or -1 and 2/3

7 0

3 years ago

Read 2 more answers

Find the distance between the points A (13, 2) and B (7, 10).

Aliun [14]

Answer:

Step-by-step explanation:

d = 10

For:

(X1, Y1) = (13, 2)

(X2, Y2) = (7, 10)

Distance Equation Solution:

d=(7−13)2+(10−2)2−−−−−−−−−−−−−−−−−√

d=(−6)2+(8)2−−−−−−−−−−√

d=36+64−−−−−−√

d=1–√00

d=10

4 0

2 years ago

Find derivative problem Find B’(6)

dalvyx [7]

Answer:

$B^\prime(6) \approx -28.17$

Step-by-step explanation:

We have:

$\displaystyle B(t)=24.6\sin(\frac{\pi t}{10})(8-t)$

And we want to find B’(6).

So, we will need to find B(t) first. To do so, we will take the derivative of both sides with respect to x. Hence:

$\displaystyle B^\prime(t)=\frac{d}{dt}[24.6\sin(\frac{\pi t}{10})(8-t)]$

We can move the constant outside:

$\displaystyle B^\prime(t)=24.6\frac{d}{dt}[\sin(\frac{\pi t}{10})(8-t)]$

Now, we will utilize the product rule. The product rule is:

$(uv)^\prime=u^\prime v+u v^\prime$

We will let:

$\displaystyle u=\sin(\frac{\pi t}{10})\text{ and } \\ \\ v=8-t$

Then:

$\displaystyle u^\prime=\frac{\pi}{10}\cos(\frac{\pi t}{10})\text{ and } \\ \\ v^\prime= -1$

(The derivative of u was determined using the chain rule.)

Then it follows that:

$\displaystyle \begin{aligned} B^\prime(t)&=24.6\frac{d}{dt}[\sin(\frac{\pi t}{10})(8-t)] \\ \\ &=24.6[(\frac{\pi}{10}\cos(\frac{\pi t}{10}))(8-t) - \sin(\frac{\pi t}{10})] \end{aligned}$