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vlada-n [284]
3 years ago
5

Line segment YV of rectangle YVWX measures 24 units.

Mathematics
2 answers:
oksian1 [2.3K]3 years ago
7 0

Answer: YX=13.85\ units

Step-by-step explanation:

<h3> The complete exercise is: "Line segment YV of rectangle YVWX measures 24 units. What is the length of line segment YX?"</h3><h3> The missing figure is attached.</h3>

Since the figure is a rectangle, you know that:

WV=YX\\\\YV=XW=24

Notice that the segment YV divides the rectangle into two equal Right triangles.

Knowing the above, you can use the following Trigonometric Identity:

tan\alpha =\frac{opposite}{adjacent}

You can identify that:

\alpha =30\°\\\\opposite=YX\\\\adjacent=YV=24

Therefore, in order to find the length of the segment YX, you must substitute values into  tan\alpha =\frac{opposite}{adjacent} and then you must solve for YX.

You get that this is:

tan(30\°)=\frac{YX}{24}\\\\(24)(tan(30\°))=YX\\\\YX=13.85

Nikitich [7]3 years ago
5 0

Answer:

8 StartRoot 3 EndRoot units

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3 years ago
What is the exact value of sin(105°)?<br><br><br>ANSWER - D) sqrt(2 + sqrt3)/2
Fofino [41]

Answer:

\sin 105^{\circ} = \frac{\sqrt{6}+\sqrt {2}}{4}

Step-by-step explanation:

We can use the following trigonometrical identity:

\sin (\alpha - \beta) = \sin \alpha \cdot \cos \beta - \cos \alpha \cdot \sin \beta (1)

Where \alpha, \beta are angles, measured in sexagesimal degrees.

If we know that \alpha = 135^{\circ} and \beta = 30^{\circ}, then the value of the given function is:

\sin 105^{\circ} = \sin 135^{\circ}\cdot \cos 30^{\circ} - \cos 135^{\circ}\cdot \sin 30^{\circ}

\sin 105^{\circ} = \left(\frac{\sqrt{2}}{2} \right)\cdot \left(\frac{\sqrt{3}}{2}\right)-\left(-\frac{\sqrt{2}}{2} \right)\cdot \left(\frac{1}{2}\right)

\sin 105^{\circ} = \frac{\sqrt{6}}{4}+\frac{\sqrt{2}}{4}

\sin 105^{\circ} = \sqrt{\frac{6}{16} }+\sqrt{\frac{2}{16} }

\sin 105^{\circ} = \sqrt{\frac{3}{8} }+\sqrt{\frac{1}{8} }

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3 years ago
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An aluminum can is a right cylinder. Find the amount of paper needed for the can's label and the total
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Answer:

Label: About 527.9 square centimeters

Aluminum: About 835.7 square centimeters

Step-by-step explanation:

Amount of paper needed for the label:

You can imagine taking off the label and unrolling it, forming a rectangle. The height of this rectangle will be the height of the cylinder, while the length of the rectangle will be the circumference of the cylinder. Therefore, the area of that rectangle will be 2\pi r h= 2 \cdot \pi \cdot 7 \cdot 12\approx 527.9.

Amount of aluminum needed for the can:

This time, you need to add in the top and bottom of the can as well, which each have area \pi r^2. Together, they have area 2\pi r^2=2\cdot \pi \cdot 7^2\approx 307.9. Adding this to the area of the sides, you get a total of about 835.7 square centimeters.

Hope this helps!

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