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Mathematics

1 answer:

valentina_108 [34]3 years ago

7 0

Answer: s^1=1/(w/2)/(1/2)^2+h^2

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How to solve 4n²-3n-7=0

almond37 [142]

$4n^2-3n-7=0\\ \\ a=4, \ \ b=-3 \ \ c=-7\\ \\ \Delta = b^{2}-4ac = (-3)^{2}-4*4* (-7)= 9+112=121$

$x_{1}=\frac{-b-\sqrt{\Delta }}{2a} =\frac{ 3-\sqrt{ 121}}{2*4}=\frac{ 3-11}{8}= \frac{-8 }{ 8}=-1 \\ \\x_{2}=\frac{-b+\sqrt{\Delta }}{2a} =\frac{ 3+\sqrt{ 121}}{2*4}=\frac{ 3+11}{8}= \frac{14 }{ 8}= \frac{7}{4}=1\frac{3}{4}$

4 0

3 years ago

Read 2 more answers

Bill Gates wrote a computer program that generates three random numbers

Allushta [10]

Answer:

1/1000

Step-by-step explanation:

The probability of two independent events A, B (independent = events that do not depend on each other) is given by the product of the individual probabilities of A and B:

$p(AB)=p(A)\cdot p(B)$ (1)

In this problem, the single event is "getting a 3" when extracting a random number between 1 and 10.

The total number of possible outcomes is

n = 10

While the number of succesfull outcomes (getting a 3) is only one:

$s=1$

So, the probability of drawing a 3 in 1 draw is

$p(3)=\frac{s}{n}=\frac{1}{10}$

Then, we want to find the probability of getting three "3" in 3 consecutive generations. These events are independent events, so we can use rule (1) to find the total probability, and we get:

$p(333)=p(3)p(3)p(3)=(\frac{1}{10})(\frac{1}{10})(\frac{1}{10})=\frac{1}{1000}$