Question

\dfrac12(10x + 20y +10z) = 2 1 ​ (10x+20y+10z)=start fraction, 1, divided by, 2, end fraction, left parenthesis, 10, x, plus, 20, y, plus, 10, z, right parenthesis, equals

Answer 1

Answer:

5x + 10y + 5z

Step-by-step explanation:

Given the expression

$\frac{1}{2}(10x+20y+10z)$

Expand the parenthesis using the distributive law;

$\frac{1}{2}(10x)+ \frac{1}{2}(20y)+\frac{1}{2}(10z)\\= \frac{10x}{2} + \frac{20y}{2} + \frac{10z}{2}\\= 5x + 10y + 5z$

Hence the required solution is 5x + 10y + 5z