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aksik [14]
3 years ago
10

\dfrac12(10x + 20y +10z) = 2 1 ​ (10x+20y+10z)=start fraction, 1, divided by, 2, end fraction, left parenthesis, 10, x, plus, 20

, y, plus, 10, z, right parenthesis, equals
Mathematics
1 answer:
iragen [17]3 years ago
6 0

Answer:

5x + 10y + 5z

Step-by-step explanation:

Given the expression

\frac{1}{2}(10x+20y+10z)\\

Expand the parenthesis using the distributive law;

\frac{1}{2}(10x)+ \frac{1}{2}(20y)+\frac{1}{2}(10z)\\= \frac{10x}{2} + \frac{20y}{2} + \frac{10z}{2}\\= 5x + 10y + 5z

Hence the required solution is 5x + 10y + 5z

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