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JulijaS [17]
3 years ago
11

Pio;uyltkjdthsgfxhcvjbk.nl

Mathematics
2 answers:
ruslelena [56]3 years ago
6 0

Answer :pio;uyltkjdthsgfxhcvjbk.nl

iuifyjgchvjblgkufyjdhgxfbv nm,jkghgbv nmbjgkuf,jhcmvjgU"Fy;dlc.v/H

g'f;c.xcv/bhg'fh;cj.

Step-by-step explanation:

bekas [8.4K]3 years ago
4 0

Answer:

vbgfdcvbnmkkhgfcv bnm,l

Step-by-step explanation:

Elo by the way :D

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Write a real word problem that can be represented by the equation 3/4c=21
svetlana [45]

How many 3/4 cups of milk would be needed to make 21 cups of milk for a large recipe?

4 0
3 years ago
Carlos looks for bird food to feed Julio, his pet parakeet. He feeds Julio a total of cup of food each day. Julio is fed twice e
aleksandrvk [35]
Well if he feeds him a cup a day and feeds him 2 times a day then you would divide one cup by two which equals half a cup. he feeds julio half a cup each time

3 0
3 years ago
A game decreased in price by 1/5. After the reduction it was priced at £48. What was the original price of the game?
Agata [3.3K]

Answer:

1/5 is equal to 20% so you multiply 48 by .20 and you get 9.6 and your take 9.6 and add it to 48. your answer will be 57.6

3 0
3 years ago
Read 2 more answers
A candidate took a phone poll of 114 people and found that 87 said they would vote for the other person.There are 9918 people in
Dima020 [189]
87 / 114 = x / 9918....87 people to 114 = x people to 9918
cross multiply
(114)9x) = (87)(9918)
114x = 862866
x = 862866/114
x = 7569 <=== 
4 0
3 years ago
Read 2 more answers
Again ... Commute times in the U.S. are heavily skewed to the right. We select a random sample of 500 people from the 2000 U.S.
VladimirAG [237]

Answer:

We conclude that the mean commute time in the U.S. is less than half an hour.

Step-by-step explanation:

We are given that a random sample of 500 people from the 2000 U.S. Census is selected who reported a non-zero commute time.

In this sample the mean commute time is 27.6 minutes with a standard deviation of 19.6 minutes.

Let \mu = <u><em>mean commute time in the U.S..</em></u>

So, Null Hypothesis, H_0 : \mu \geq 30 minutes      {means that the mean commute time in the U.S. is more than or equal to half an hour}

Alternate Hypothesis, H_A : \mu < 30 minutes     {means that the mean commute time in the U.S. is less than half an hour}

The test statistics that would be used here <u>One-sample t-test statistics</u> as we don't know about population standard deviation;

                           T.S. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean commute time = 27.6 minutes

            s = sample standard deviation = 19.6 minutes

            n = sample of people from the 2000 U.S. Census = 500

So, <u><em>the test statistics</em></u>  =  \frac{27.6 -30}{\frac{19.6}{\sqrt{500} } }  ~ t_4_9_9

                                       =  -2.738

The value of t test statistic is -2.738.

Since, in the question we are not given with the level of significance so we assume it to be 5%. <u>Now, at 5% significance level the t table gives critical values of -1.645 at 499 degree of freedom for left-tailed test.</u>

Since our test statistic is less than the critical value of t as -2.378 < -1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u>we reject our null hypothesis.</u>

Therefore, we conclude that the mean commute time in the U.S. is less than half an hour.

4 0
4 years ago
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