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cestrela7 [59]
3 years ago
8

HELP ASAP I NEED THIS TODAY ONLY I WILL MARK BRAINLIEST

Mathematics
1 answer:
Serjik [45]3 years ago
4 0

Answer:

Step-by-step explanation:

1a. 14

1b. it's positive

2. If we were to just go with an estimation, i would say anywhere between 50-60, but I'm going with 50

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An angle measures 62° less than the measure of its complementary angle. What is the measure of each angle? (i need two answers p
postnew [5]

Answer:

28° 62°

Step-by-step explanation:

Hope this helps :)

8 0
3 years ago
15
Butoxors [25]

Step-by-step explanation:

1/2 represents every fraction, where the denominator (bottom part) is twice the numerator (top part).

like 4/8 or 6/12 or 128/256 or ...

what do we need in the denominator to calculate with 15/16 ?

the same : 16.

and what is half of 16 ? 8.

so, we need the 1/2 based on 16th = 8/16.

so, the dog ate 8/16 (1/2) of the original 15/16.

what was left was

15/16 - 8/16 = 7/16 pound

7 0
2 years ago
Y=-4x-3 if the slope was changed to -.50,and the y intercept remained the same?​
yanalaym [24]
The new slope would now be 2 so y=2x-3
3 0
3 years ago
A rational function g is given below. Find all values of a for which ​g(a)=16. g(x)=(4)/(x+1)+(20)/(x^(2)+2x+1)
aliina [53]

Answer:

a = 2/3

Step-by-step explanation:

(4(x+1) + 20 )/(x+1) = 16

4x + 4 + 20 = 16x + 16

12x = 8

x = 2/3

3 0
3 years ago
Find a polynomial P(x) with real coefficients having a degree 4, leading coefficient 4, and zeros 3-i and 4i.
Alisiya [41]

now, this polynomial has roots of 3-i and 4i, namely 3 - i and 0 + 4i.

let's bear in mind that a complex root never comes all by her lonesome, her sibling is always with her, the conjugate, so if 3 - i is there, 3 + i is also coming along, likewise if 0 + 4i is there, her sibling 0 - 4i is also there.

\bf \begin{cases} x=3-i\implies &x-3+i=0\\ x=3+i\implies &x-3-i=0\\ x=4i\implies &x-4i=0\\ x=-4i\implies &x+4i=0 \end{cases}\\\\[-0.35em] ~\dotfill\\\\ (x-3+i)(x-3-i)(x-4i)(x+4i)=\stackrel{y}{0} \\[2em] \underset{\textit{difference of squares}}{[(x-3)+i][(x-3)-i]}\underset{\textit{difference of squares}}{[x-4i][x+4i]}=0

\bf [(x-3)^2-i^2][x^2-(4i)^2]=y\implies [(x-3)^2-(-1)][x^2-(4^2i^2)]=0 \\[2em] [(x-3)^2-(-1)][x^2-(16(-1))]=0\implies [(x-3)^2+1][x^2+16]=0 \\[2em] [(x^2-6x+9)+1][x^2+16]=y\implies (x^2-6x+10)(x^2+16)=0 \\\\\\ x^4-6x^3+10x^2+16x^2-96x+160=0 \\\\\\ x^4-6x^3+26x^2-96x+160=0 \\\\\\ \stackrel{\textit{multiplying both sides by 4}}{4(x^4-6x^3+26x^2-96x+160)=4(0)} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill 4x^4-24x^3+104x^2-384x+640=y~\hfill

3 0
3 years ago
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