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natka813 [3]
3 years ago
6

A recent Harris poll asked a random sample of 1016 adults nation-wide whether or not they smoked cigarettes. 22% said they smoke

d. Based on this sample, can you conclude that... the expected value for the percent of all adults world-wide who would say they smoked cigarettes is 22%? the expected value for the percent of students at UI who would say they smoked cigarettes is 22%? the expected value for the percent of professors at UI who would say they smoked cigarettes is 22%? the expected value for the percent of all US adults who would say they smoked cigarettes is 22%?
Mathematics
1 answer:
photoshop1234 [79]3 years ago
8 0

Answer:

A recent Harris poll asked a random sample of 1016 adults nation-wide whether or not they smoked cigarettes. 22% said they smoked. Based on this sample, can you conclude that...

a.) The expected value for the percent of all adults world-wide who would say they smoked cigarettes is 22%?

b). The expected value for the percent of students at UI who would say they smoked cigarettes is 22%?

c). The expected value for the percent of professors at UI who would say they smoked cigarettes is 22%?

d). The expected value for the percent of all US adults who would say they smoked cigarettes is 22%?

The correct answer is

d).The expected value for the percent of all US adults who would say they smoked cigarettes is 22%?

Step-by-step explanation:

The expected value is arrived at by finding the product of a possible output and the probability that the output will occur and summing up the results. Expected value can be used for investment management to calculate options and make decisions most likely to bring about the desired gain. The random variable provides categorisation of the outcomes of the game while the expected provides the probability of aan outcome

In the above, the source of the sample is nationwide whereby 22 % said they smoked therefore it cannot be applied to a different population that has a different expected value for the same survey.

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Step-by-step explanation:

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A food production company is choosing between two suppliers of grain. Supplier A sells grain for $5.25 per bushel plus
ANTONII [103]

Answer:

Supplier A: 5.25 per bushel and deliver fee of 3 per bushel

Supplier B: 6.50 per busher and flat delivery fee of $1500 each week

500 bushels of grain each week.

Supplier A: 5.25x + 3x = 5.25(500) + 3(500) =  2,625 + 1,500 = 4,125

Supplier B: 6.50x + 1500 = 6.50(500) + 1500 = 3,250 + 1,500 = 4,750

Supplier B would cost more if the company buys 500 bushels of grain per week.

Step-by-step explanation:

6 0
3 years ago
We take a milk carton from the refrigerator and put it on the table at room temperature. We assume that the temperature of the c
Kisachek [45]
We can solve this problem using separation of variables.

Then apply the initial conditions

EXPLANATION

We were given the first order differential equation

\frac{dT}{dt}=k(T-a)

We now separate the time and the temperature variables as follows,

\frac{dT}{T-a}=kdt

Integrating both sides of the differential equation, we obtain;

ln(T-a)=kt +c

This natural logarithmic equation can be rewritten as;

T-a=e^{kt +c}

Applying the laws of exponents, we obtain,

T-a=e^{kt}\times e^{c}

T-a=e^{c}e^{kt}

We were given the initial conditions,

T(0)=4

Let us apply this condition to obtain;

4-20=e^{c}e^{k(0)}

-16=e^{c}

Now our equation, becomes

T-a=-16e^{kt}

or

T=a-16e^{kt}

When we substitute a=20,
we obtain,

T=20-16e^{kt}

b) We were also given that,

T(5)=8

Let us apply this condition again to find k.

8=20-16e^{5k}

This implied

-12=-16e^{5k}

\frac{-12}{-16}=e^{5k}

\frac{3}{4}=e^{5k}

We take logarithm to base e of both sides,

ln(\frac{3}{4})=5k

This implies that,

\frac{ln(\frac{3}{4})}{5}=k


k=-0.2877

After 15 minutes, the temperature will be,


T=20-16e^{-0.2877\times 15}

T=20-0.21376


T=19.786

After 15 minutes, the temperature is approximately 20°C


6 0
3 years ago
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