Answer:
B=5522.33kg/h
C=478.11kg/h
Explanation:
Hi! It's a mass balance. First we have to determine the inflow.
mass flow rate = 36000kg / 6h = 6000kg / h
We define the input variable
- input flow (A) = 6000kg / h
-XgA = percentage of fat in A = 0.04
We define output variables.
- skim milk (B)
-creme (C)
-XgB = fat percentage at B = 0.0045
-XgC = percentage of fat in C = 0.45
Then we can start with the balance.
As a general rule, the mass balance is:
Input = Output
Balance sheet
1) A = B + C
Fat balance
2) A * XgA = B * XgB + C * XgC
Now we can solve.
We replace and clear B in equation 2
6000kg / h * 0.04 = B * 0.0045 + C * 0.45
B = (240kg / h) /0.045-C*0.45/0.0045
3) B = 53333.33kg / h-C * 100
We replace equation 3 in 1 and clear C
A = B + C
6000kg / h = 53333.33kg / h-C * 100 + C
C=(6000kg/h-53333.33kg/h)/(-99)
C=478.11kg/h
We replace C in equation 3 and calculate B
B = 53333.33kg / h-478.11kg/h * 100
B=5522.33kg/h
Then we have the values of the outflows.
C=478.11kg/h
B=5522.33kg/h
