Answer:
Acceleration = (change in speed) / (time for the change)
Change in speed= (0 - 26 km/hr) = -26 km/hr
(-26 km/hr) x (1,000 m/km) x (1 hr / 3,600 sec) = -7.222 m/sec
Average acceleration = (-7.222 m/s) / (22 min x 60sec/min) = -0.00547 m/sec²
Average speed during the stopping maneuver =
(1/2) (start speed + end speed) = 13 km/hr = 3.6111 m/sec
Explanation:
Answer:
5.81 moles
Explanation:
To find the number of moles (n) in 3.5 x 10²⁴ molecules of methane gas, we divide the number of molecules by Avagadro's number (nA). That is,
n = number of molecules ÷ 6.02 × 10²³
According to this question, 3.5 x 10^24 molecules of methane gas was given, hence,
n = 3.5 × 10²⁴ ÷ 6.02 × 10²³
n = 3.5/6.02 × 10(24 - 23)
n = 0.5814 × 10¹
n = 5.81 moles
Use the equation Q = mCT.
Q is the amount of energy in joules.
m is the mass in grams.
C is the specific heat of water (4.184 J/g °C).
T is the change in temperature.
0.700 pints = 331.224 g of water
Q = (331.224 g)(4.184 J/g °C)(100° C - 30° C)
Q = 97,008.885 J
Divide by 1,000 to convert to kilojoules:
97.009 kJ
852 x 40.0= 4260 x v2
<span>v2= 8 L </span>
<span>b) 852 x 40 = p2 x 69.0 </span>
<span>p2= 494 torr</span>
Answer:
Half Cell (1)oxidation reaction (2) redox reaction
Anode----(1)and(2) electrochemical cell at which oxidation occurs
Cathode---(1)and(2)electrochemical cell at which reduction
Electrolytes----(1)ammonium chloride------
Oxidation Reaction --- (1)in Anode(2)in Anode
Reduction Reaction----(1)in Cathode(2)in cathode
Bridge---(1)Zinc–carbon battery(2) Galvanic cell
Relative size ------ (1)smaller--------(2)much larger
Explanation:
