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pishuonlain [190]
3 years ago
15

The quadrilateral ABCD has an area of 58 in2 and diagonal AC = 14.5 in. Find the length of diagonal BD if AC ⊥ BD.

Mathematics
1 answer:
diamong [38]3 years ago
4 0
So the quadrilateral is a rhombus. RSM Is hard and etc...
Anyways if the area =58^{2} and we know that one diagonal is 14.5 inches and we know that the area of a rhombus is 
\frac{D^{1} * D^{2}}{2}   =
then we can do inverse operation and do
\frac{54}{14.5} = 4 
4 * 2 because of the inverse operation has to be done to get the right answer and then you get the length of diagonal 2 is 8 in 
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Two distinct integers, $x$ and $y$, are randomly chosen from the set $\{1,2,3,4,5,6,7,8,9,10\}$. What is the probability that $x
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24 i really dont know what 

7 0
3 years ago
The Chiquita Bananas are on sale for $3.72 for 6 pounds of bananas. Miller's Bananas are on sale for $0.64 per pound. Which comp
puteri [66]

Answer:

millers is cheper instead of 3.72 for 6 pond 0.64 is better because what if some one only wants 1 pond then they only should pay 64 cents

Step-by-step explanation:

3 0
3 years ago
4x+y=8 and x+3y=8 graphed
IRISSAK [1]
standard \ linear \ equation\ :\\\\y=ax+b\\\\ \begin{cases} 4x+y=8\ \ |\ subtract\ 4x\ to\ both\ sides\\ x+3y=8 \ \ |\ subtract\ x\ to\ both\ sides \end{cases}\\\\\begin{cases} y=-4x+8 \\ 3y=-x+8\ \ | \ divide \ each \ term \ by \ 3 \end{cases}

\begin{cases} y=-4x+8 \\ y=-\frac{1}{3}x+\frac{8}{3} \end{cases}\\\\y=-4x+8\\ To \ find \ the \ x-axis \ intersection \ point, \\set \ y \ equal \ to \ zero \ and \ solve \ for \ x : \\ \\y=0 \ \to 0=-4x+8\\\\4x=8 \ \ | \ divide \ both \ sides\ by\ 4 \\\\x=2\\\\ point : \ \ (2,0)
 
To \ find \ the \ y-axis \ intersection \ point, \\set \ x \ equal \ to \ zero \ and \ solve \ for \ y : \\ \\x=0 \ \to y=-4 \cdot 0+8\\ y=8 \\ point: \ \ (0,8)


y=-\frac{1}{3}x+\frac{8}{3}\\\\ \ the \ x-axis \ intersection \ point \\ \\y=0 \ \to 0=-\frac{1}{3}x+\frac{8}{3}\\ \frac{1}{3}x=\frac{8}{3} \ \ | \ multiply\ both\ sides\ by\ 3 \\\\x=8 \\\\point: \ \ (8,0)

the \ y-axis \ intersection \ point \\ \\x=0 \ \to y=-\frac{1}{3} \cdot 0+\frac{8}{3} \\ y=\frac{8}{3} \\ point : \ \ (0,\frac{8}{3})


Answer :\\\\ \begin{cases} y=-4x+8 \ \ | \ multiply \ each \ term \ by \ (-3) \\ 3y=-x+8 \end{cases}\\\begin{cases} -3y=12x-24 \\ 3y=-x+8 \end{cases}\\+-------\\0=11x-16\\11x=16\ \ | \ divide \ both \ sides\ by\ 11\\x=\frac{16}{11}

y=-4 \cdot \frac{16}{11}+8 \\ y=- \frac{ 64}{11}+\frac{88}{11}\\y= \frac{24}{11}\\\\\begin{cases} x=\frac{16}{11} \\ y=\frac{24}{11} \end{cases}


3 0
3 years ago
Fabio and Gwen are saving money to buy a new gaming station. They need at least $510 to purchase the new gaming station. Gwen we
vaieri [72.5K]

x represents the number of lawns weeded by Gwen and y represents the number of dogs walked by Fabio.

Gwen charges $12 each time she weeds a yard and Fabio charges $9 each time he walks a dog.

So, for x number of weeds, Gwen earned 12x and for y number of dogs walked, Fabio earned 9y.

They need at least $510 to purchase the new gaming station.

Therefore,

12x + 9y ≥ 510

Also, the number of dog walks that Fabio has scheduled should not be more than twice the number of yards Gwen has scheduled to weed.

Therefore,

y ≤ 2x

Also, Fabio will walk at least 25 dogs.

Therefore,

y ≥ 25

Hence, the constraints are:

12x + 9y ≥ 510

y ≤ 2x

y ≥ 25

8 0
4 years ago
What is the solution to the system of linear equations shown? picture attached
OLga [1]
Answer: C (0,3) because the two lines meet at the point (0,3)
7 0
3 years ago
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