Step-by-step explanation:

Answer:
as in pic below
Step-by-step explanation:
Answer:
5in x 10in
Step-by-step explanation:
Solution:
1. You have to assume that the ring will land on the board and as a result, just focus on one rectangle of the board since they are all the same size.
2. For the ring to land entirely inside the rectangle, the center of the ring needs to be 1.5 inches inside the border (radius is 1.5 inches), so the "winning rectangle" will have dimensions:
L = (x - 2(1.5)) = x - 3
w = (2x - 2(1.5)) = 2x-3.
3. Now, we will set up and solve our geometric probability equation. The winning rectangle's area of (x-3)*(2x-3) divided by the total rectangle's area of x*(2x) = 28%
(2x-3)*(x-3)/(2x^2) = .28
2x^2 - 9x + 9 = .56x^2
1.44x^2 - 9x + 9 = 0
4 . Now you can plug that in the quadratic formula and get the solutions x = 1.25 or 5. However, it cannot by 1.25 because that is too small of a dimension for the the circle with diameter of 3 to fit in, the answers has to be 5.
5. As a result, the dimensions of the rectangles are 5in x 10in.
Option A is correct.
If we evaluate the function at
, i.e. at the beginning, we have

with each minute, you multiply the current number of cell by 2, so they double every minute.
Option B is incorrect, because if the number of cells increases by 2 every minute, the function would be

Option C is incorrect, because after one minute (i.e. when x=1) we have

cells, so 75 is not the number of cells after one minute
Option D is incorrect in both the initial value and the behaviour of the function