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3 years ago

Choices: One-sixth cups Five-sixths cups 1 and two-thirds cups 1 and 5 / 6 cups

Mathematics

1 answer:

navik [9.2K]3 years ago

3 0

Answer:

Patel will require more orange juice = $\frac{371}{660}$ cups

Step-by-step explanation:

Patel needs the orange juice for his family = 3 cups

He needs more orange juice = 3 cups - Sum of juice squeezed from different oranges

$=3-(\frac{13}{15}+\frac{1}{5}+\frac{9}{20}+\frac{5}{11}+\frac{7}{15})$

L.C.M. of the denominators = 660

$=3-\frac{572+132+297+300+308}{660}$

$=3-\frac{1609}{660}$

= $\frac{1980-1609}{660}$

= $\frac{371}{660}$

Therefore, amount of orange juice required more = $\frac{371}{660}$ cups

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I dont undertand ;-;

dexar [7]

Answer:3/8 is equal to 3/4 and 4/6 is equal to 2/3.

Step-by-step explanation:

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2 years ago

Can someone help me with this question? You don’t really have to tell me the answer but just how to solve it.

Veronika [31]

part A

if the paperbacks are 40% less, that means 100% - 40% = 60%, they actually are 60% of the price of the hardcover ones.

$\bf \begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{60\% of 24.99}}{\left( \cfrac{60}{100} \right)249.99}\implies 14.994$

part B

so, if they return it, they get 1/3 credit, if they try to sell it, is half off, which is more than 1/3. 22 got damaged.

$\bf \stackrel{\textit{damaged books at half-price}}{(22\cdot 14.994)\cfrac{1}{2}\implies 164.934}~\hfill \stackrel{\textit{damaged books at one-third price}}{(22\cdot 14.994)\cfrac{1}{3}\implies 109.956} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill 164.934 - 109.956 = 54.978~\hfill$

part C

$\bf \textit{First Day}~\hfill \stackrel{hardcover}{3(24.99)}+\stackrel{paperback}{8(14.994)}+\stackrel{damaged}{3\left( 14.994\cdot \frac{1}{2} \right)} \implies 217.413 \\\\\\ \textit{Second Day}~\hfill \stackrel{hardcover}{4(24.99)}+\stackrel{paperback}{5(14.994)}+\stackrel{damaged}{8\left( 14.994\cdot \frac{1}{2} \right)}\implies 234.906 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill \boxed{17.493}$

I don't think she is incorrect, $17.5 is close to $20, she didn't say it was exactly $20, just thereabouts, and 17.5 is around that much.

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3 years ago

Find the midpoint of the segment with the following endpoints. (10,6) and (6,10)

svlad2 [7]

Answer:

(8,8)

Step-by-step explanation:

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3 years ago

A population of plastic chairs in a factory has a weight's mean of 1.5 kg and a standard deviation of 0.1 kg . Suppose a sample

Firlakuza [10]

Answer:

0.9544 = 95.44% probability that the sample mean will be within +0.02 of the population mean.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

$\mu = 1.5, \sigma = 0.1, n = 100, s = \frac{0.1}{\sqrt{100}} = 0.01$

What is the probability that the sample mean will be within +0.02 of the population mean?

Sample mean between 1.5 - 0.02 = 1.48 kg and 1.5 + 0.02 = 1.52 kg, which is the pvalue of Z when X = 1.52 subtracted by the pvalue of Z when X = 1.48. So

X = 1.52

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{1.52 - 1.5}{0.01}$

$Z = 2$

$Z = 2$ has a pvalue of 0.9772

X = 1.48 

$Z = \frac{X - \mu}{s}$

$Z = \frac{1.48 - 1.5}{0.01}$

$Z = -2$

$Z = -2$ has a pvalue of 0.0228

0.9772 - 0.0228 = 0.9544

0.9544 = 95.44% probability that the sample mean will be within +0.02 of the population mean.

3 0

3 years ago

Write an equation to find the nth term. Then find ₐ₂₄<br> 1, 3, 5, 7,.......

kirill115 [55]

The equation to find the nth term is:

an = a+(n-1)d

Where a is the first term in the sequence, which is 1 and d is the difference, which in this sequence the next term is found by adding 2 to the previous term, so d = 2 and n is the term you want to find.

The equation is:

an = 1 + (n-1)2

a24 = 1 + (24-1)2 = 1 + 23(2) = 1+46 = 47

5 0

3 years ago