Step-by-step explanation:
It is given that, two boys are throwing a baseball back and forth.
Height above ground, h₀ = 4 ft
Initial velocity of child, u = 36 ft/s
Acceleration due to gravity, a = -16 ft/s²
The equation of projectile motion is given by :

According to the given condition,

h(t) = 2.356 meters
Height of the ball at t = 2 s

h = 12 ft
So, at t = 2 seconds the height of the ball is 12 feet from the ground. Hence, this is the required solution.