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3 years ago

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PLEASE HELP ME THIS IS TIMED!!! PLEASE HELP!!!! I WILL MARK YOU BRAINIEST IF YOUR ANSWER IS CORRECT!!!!!!! AND NO LINKS OR I WIL

L TRACK YOU DOWN!! I HAVE TRACKED PEOPLE BEFORE!! SO NO LINKS!!!!!!! I WILL MARK YOU BRAINIEST IF YOUR ANSWER IS CORRECT!!!!!!!

1 answer:

Yuliya22 [10]3 years ago

3 0

Answer:

14 out of 24 passed the test and did the homework, which is 0. 583 or 58.3%

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I need help please it’s ASAP

malfutka [58]

The interquartile range of the data is equal to 2.18.

<h3>What is an interquartile range?</h3>

The interquartile range is a measure of where a data set's "middle fifty" is located. Whereas a range is a measure of where the start and end of a set are, an interquartile range is a measure of where the majority of the values are.

Given data is { 1.56,1.77,2.22,2.35,2.45,2.77,3.26,4.35,5.23,6.02}.

The upper limit is, and the median is 2.22.

{ 1.56,1.77,<u>2.22</u>,2.35,2.45,2.77}

The lower limit is, and the median is 4.35.

{2.77,3.26,<u>4.35</u>,5.23,6.02}

The interquartile range will be calculated as,

IQR = 4.35 - 2.22

IQR = 2.18

To know more about interquartile range follow

brainly.com/question/21270410

#SPJ1

5 0

1 year ago

If when simplified results to a unit fraction and

tangare [24]

Answer:

a ≤ 39 ≠ 1

Step-by-step explanation:

3 0

2 years ago

Can someone answer this question answer it correctly please and show work please

3241004551 [841]

Answer:

42) 254.47 ft²

43) 56 pendants

Step-by-step explanation:

42)

The radius of a circle is equal to half of its diameter.

Diameter = 18 feet

Radius = Diameter ÷ 2 = 18 ÷ 2 = 9 feet

Area of a circle = π $r^{2}$

Substitute in known value of r

Area = π $9^{2}$

Substitute in pi

Area = 3.14 * $9^{2}$

Solve exponent

Area = 3.14159265359 * 81

Area = 254.4690049408

(Rounds to 254.47)

254.47 ft²

43)

$1\frac{1}{2} =$ 1.5 ounces per pendant

3 pieces of silver:

$1\frac{7}{8}$ pounds

14 ounces

$2\frac{1}{2}$ pounds

Convert to improper fractions (1 lb = 16 ounces)

$\frac{15}{8}$ pounds

$\frac{14}{16}$ pounds

$\frac{5}{2}$ pounds

Find a common denominator for the fractions

$\frac{30}{16}$ pounds

$\frac{14}{16}$ pounds

$\frac{40}{16}$ pounds

Add

$\frac{30}{16}$ + $\frac{14}{16}$ + $\frac{40}{16}$

$\frac{84}{16}$ pounds

Find how many pendants can be made out of this amount

$\frac{84}{16}$ pounds

Convert back to ounces (1 lb = 16 ounces)

84 ounces

Amount to make one pendant:

$1\frac{1}{2}$ ounces

Convert to decimal

1.5 ounces

Divide 84 by amount of silver per pendant

84 ÷ 1.5

56

The maximum number the pendants that the manufacturer can make is 56

Hope this helps :)

8 0

3 years ago

What’s 28,561 in expanded form

inna [77]

Step-by-step explanation:

2×10,000 + 8×1000 + 5×100+6×10+1

6 0

3 years ago

Margot is sewing a ribbon on a seam along the perimeter of a square pillow. The side length of the pillow is 23-1 inches. She pl

Sergio [31]

Answer:

D. 4(2x² + 4x - 6); 130.0 inches

Step-by-step explanation:

Margot is sewing a ribbon on a seam along the perimeter of a square pillow. The side length of the pillow is 2x²+1 inches. She plans to make a similar pillow, including the ribbon, whose side length is 4x−7 inches. What expression can be used for the length of ribbon that she needs for both pillows, and what is the length if x = 3.5?

2x2+4x−6; 22.0 inches

2x2+4x−6; 32.5 inches

4(2x2+4x−6;) 88.0 inches

4(2x2+4x−6;) 130.0 inches

Perimeter of a square = 4 * side length

1- First square pillow

length = 2x²+1 in

Perimeter of first pillow = 4 * (2x²+1) in

Second square pillow

length = 4x-7 in

Perimeter of second pillow = 4(4x-7) in

Total ribbon length required = perimeter of first square pillow + perimeter of second square pillow

Total ribbon length required = 4(2x²+1) + 4(4x-7)

Factorise

4 is the common factor

=4(2x²+1)+(4x-7)

=4(2x²+1+4x-7)

=4(2x²+4x-6)

Total ribbon length required=4(2x²+4x-6)

If x=3.5

Total ribbon length required=4(2x²+4x-6)

=4{2(3.5)²+4(3.5)-6}

=4{2(12.25)+14-6)

=4(24.5+14-6)

=4(32.5)

=130.0 inches

6 0

3 years ago