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SVEN [57.7K]
1 year ago
14

Sin500-sin700+sin100​

Mathematics
1 answer:
EastWind [94]1 year ago
7 0

Answer:

−1.518108

Step-by-step explanation:

pretty sure this is it, if not just message me and ill be more than happy to help you out :)

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Suppose that the middle 68% of speeding ticket fines on a highway fall between 93.18 and 118. Give an approximate estimate of th
Anton [14]

Answer:

The approximate estimate of the standard deviation of the speeding ticket fines is of 12.41.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

Approximately 68% of the measures are within 1 standard deviation of the mean.

Approximately 95% of the measures are within 2 standard deviations of the mean.

Approximately 99.7% of the measures are within 3 standard deviations of the mean.

Middle 68% of speeding ticket fines on a highway fall between 93.18 and 118.

This means that 93.18 is one standard deviation below the mean and 118 is one standard deviation above the mean. That is, the difference between 118 and 93.18 is worth two standard deviations. So

2s = 118 - 93.18

s = \frac{(118 - 93.18)}{2}

s = 12.41

The approximate estimate of the standard deviation of the speeding ticket fines is of 12.41.

7 0
3 years ago
Quiz
valina [46]

Answer:

Step-by-step explanation:

As we know that in an hour there are 3600 seconds so

1.8 x 3600 = 6480

 6480 / 1609 = 4.02 miles / hr

  4.02 - 2.5 = 1.5( by substracting the speed)

so correct option is D which is

 Talia swims about 1.5 miles per hour faster than Alina

hope it helps

4 0
3 years ago
There are 20 students in your class. 35 of them pack a lunch.
bezimeni [28]
That doesn’t make sense. Did you mean 15?
6 0
2 years ago
HELP ASAP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Genrish500 [490]

Answer:

Well, I don't know how to graph it for you, but the slope is -2/3 and the point is (-9, 5).  So, when you graph it, from the point (-9, 5), you can go 3 units to the right and 2 units down.

6 0
3 years ago
the area of the rectangle 56cm. the length is 2cm more than x and the with is 5cm less than twice x. solve for x. round the near
sattari [20]
(x+2)(2x-5)=56

2x^2-5x+4x-10=56

2x^2-x-10=56

2x^2-x-66=0

2x^2-12x+11x-66=0

2x(x-6)+11(x-6)=0

(2x+11)(x-6)=0, since x is a measurement x>0 so:

x=6cm


7 0
3 years ago
Read 2 more answers
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