Try multiplying it
we know that 8 times 10=80 so multiply 80 by 2, then 3 then 4 untill you get close to that number so
80 times 2=160
80 times 3=240
80 times 4=320
this is over so it is more than 30 8's but less than 40 8's
so start from 320
subtract 293 from 320
320-293=27
divide 27 by 8
27/8=3 and 3/8
add that to 30
33 and 3/8 8's will fit
the teacher probably wants how many whole 8's can fit so get rid of the 3/8 and just put 33 8's
Answer:
y = -x/4 + 7/2
Step-by-step explanation:
Find the slope
( -2 , 4) ( 6 , 2)
m = (y2 - y1)/(x2 - x1)
x1 = -2
y1 = 4
x2 = 6
y2 = 2
m = ( 2 - 4)/( 6 -(-2)
m = ( 2 -4)/(6 +2)
= -2/8
= -1/4
Using point slope form equation
y - y1 = m( x - x1)
Using the second point
( 6 , 2)
x1= 6
y1=2
m = -1/4
y - 2 = -1/4(x - 6)
y - 2 = -(x - 6)/4
Open the bracket with -
y - 2 = (-x + 6)/4
y = ( -x + 6)/4 + 2
LCM = 4
y =( -x + 6 + 8)/4
y = (-x + 14)/4
Rearrange using slope intercept form
y = mx + c.
y = -x/4 + 14/4
We can break 14/4 by dividing by 2
y = -x/4 + 7/2
Answer:
Step-by-step explanation:
To solve this, we have to plug in 1/3 for x:
Try this solution (see the attachmed pictures), modify the design according to the local requirements.
Note, the points (-6;-16) and (-9;-28) are the intersection points of the parabola and the line, given in the condition.
