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qaws [65]
3 years ago
13

URGENT

Mathematics
2 answers:
goldenfox [79]3 years ago
6 0

Answer:

It's A on edge

Step-by-step explanation:

Anni [7]3 years ago
3 0

Answer:

x= 4.5

Step-by-step explanation:

90-36=54

54 divided 12 = 4.5

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11. A man is buying a lot which measures 7,860 square meters. How many
goblinko [34]

Answer:

C. 786,000 hectare

Step-by-step explanation:

This question can be solved by proportions, using conversion of units.

Each hectare has 10 000 square meters.

So 7,860 square meters is equal to:

7,860*10000 =  786,000 hectares

The answer is given by option C.

4 0
3 years ago
Erica throws a tennis ball against a wall, and it bounced bac. Which force is responsible for sending to ball back to erica
lisabon 2012 [21]
Field force is responsible
8 0
3 years ago
The opposite of 0 please help fast
Setler79 [48]

Answer: The opposite of 0 is 0

Step-by-step explanation: Hope this help :D

3 0
3 years ago
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Plss help bring up my grade please
vitfil [10]

The easiest way to solve this problem is by calculating the areas of all the sides and adding them together.

<em>Step 1; Calculate the area of the rectangular front & back</em>

A = 2 * (l * w)

  = 2 * (25 * 10)

<em>Step 2; Calculate the area of the rectangular sides </em>

A = 2 * (1 * w)

  = 2 * (55 * 10)

= 1100 ft^2

3 0
3 years ago
Which of the following are solutions to 2tanx/1-tan^2x=sqrt 3?
Tanya [424]

Answer:

A, D

Step-by-step explanation:

(\frac{2tanx}{1-tan^{2}x}) =\sqrt{3} (1)

Assume that tan x = y. Replace this into the equation (1), we have:

+) \frac{2y}{1-y^{2} } =\sqrt{3}

=> 2y = \sqrt{3}  . (1 -y^{2} ) =- \sqrt{3} .y^{2}  + \sqrt{3}

=> \sqrt{3} .y^{2}  + 2y - \sqrt{3} = 0

=> \sqrt{3} . y^{2} - 1.y + 3.y - \sqrt{3} =0

=> (\sqrt{3} . y.y - 1.y) + (\sqrt{3}.\sqrt{3}  .y - \sqrt{3}) =0

=> y.(\sqrt{3} y - 1) + \sqrt{3} (\sqrt{3} y - 1) = 0

=> (y + \sqrt{3} ).(\sqrt{3} .y -1)=0

=> y + \sqrt{3} = 0 or \sqrt{3} y -1 =0

If y + \sqrt{3} = 0

=> y = - √3

=> tan x = - √3

=> x = \frac{2\pi }{3} + n.\pi with n is an integral

If \sqrt{3} y -1 =0

=> y = 1/√3

=> tan x = 1/√3

=> x = \frac{\pi }{6} + n.\pi n is an integral

So that A, D are answers.

3 0
3 years ago
Read 2 more answers
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