Answer:
2.73> x
take away 2/3 from both sides of the inequality
<span>[3y+2/3y] / [6y^2+4y/3y+2]
Steps
First, divide fractions
= (3y + 2)(3y + 2)/3y(6y^2 + 4y)
Then... factor 3y(6y^2 + 4y): 6y^2(3y + 2)
= (3y + 2)(3y + 2)/6y^2(3y + 2)
Then, cancel the common factor: 3y + 2
= 3y + 2/6y^2</span>
Answer:
P=40
a + b + x = P
a = 3x
b = x + 5
substitute for b & y
3x + (x+5) + x = 40
Step-by-step explanation:
longest section 1 = a
mid length section 2 = b
shortest section 3 = x
P=40
a + b + x = P
a = 3x
b = x + 5
substitute for b & y
3x + (x+5) + x = 40
5x + 5 = 40
5x = 35
x = 7
b = 12
a = 21
Answer:
Step-by-step explanation:
- crate the equasion sp your equasion will look more like this 2/3 multiply by X
- Then you divide and you will get your answer that will be
