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mash [69]
3 years ago
14

Write an equation in slope-intercept form that describes the line with a slope of -2 and (5,4) is on the line

Mathematics
1 answer:
marin [14]3 years ago
3 0

Answer:

The equation in slope-intercept form will be:

  • y = -2x + 14

Step-by-step explanation:

Given

  • slope = m = -2
  • point (5, 4)

We know that the slope-intercept form of the line equation is

y = mx+b

where m is the slope of the line and b is the y-intercept

substituting m = -2 and the point (5, 4) in the slope-intercept form to get the y-intercept 'b'

y = mx+b

4 = -2(5) + b

4 = -10 + b

b = 4+10

b = 14

now substituting m = -2 and b = 14  in the slope-intercept form to get the equation in slope-intercept

y = mx+b

y = -2x + 14

Therefore, the equation in slope-intercept form will be:

  • y = -2x + 14
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From the question above 8 is the difference of d and 3.75

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Help me please and show all work.
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Jim does 12 push ups in a set. If one day he does two sets, the next day three, and the next day one, how many push ups did he d
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4 years ago
Read 2 more answers
HELP!! What is the equation of the graphed line?<br> (y=mx+b)
Anettt [7]
So to fine slope you would use the formula down below:

rise/run

So use a graphed point, 0, -5 and you rise or count up quadrants up to a point and then horizontally move to when you find that point.

So from 0,-5 go up 9 vertically, and you would be on the 4

Go horizontal 3 spots and your on a designated point.

So the rise is four and the run is 3

So 4/3 is the slope

In the y= Mx + b equation you would set the equation like this:

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The m in this formula stands for the slop and the b stands for the y-intercept

The y-intercept is the point that is on the y-axis and where it starts.
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