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mash [69]
3 years ago
14

Write an equation in slope-intercept form that describes the line with a slope of -2 and (5,4) is on the line

Mathematics
1 answer:
marin [14]3 years ago
3 0

Answer:

The equation in slope-intercept form will be:

  • y = -2x + 14

Step-by-step explanation:

Given

  • slope = m = -2
  • point (5, 4)

We know that the slope-intercept form of the line equation is

y = mx+b

where m is the slope of the line and b is the y-intercept

substituting m = -2 and the point (5, 4) in the slope-intercept form to get the y-intercept 'b'

y = mx+b

4 = -2(5) + b

4 = -10 + b

b = 4+10

b = 14

now substituting m = -2 and b = 14  in the slope-intercept form to get the equation in slope-intercept

y = mx+b

y = -2x + 14

Therefore, the equation in slope-intercept form will be:

  • y = -2x + 14
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3x - y = 2<br>and<br>2x + y = 4​
Naddik [55]

\frac{3}{1}Answer:

Step-by-step explanation:

3x-y = 2

2x+y =4

put them into slope intercept form

y=3x-2

y=-2x+4

Now, you can either graph it or use substitution

3x-2 = -2x+4

+2x +2x

5x -2 = 4

+2 +2

5x = 6

5x/5 = 6/5

x = 6/5

3x -2 = y

3(6/5) -2 = y

3 x 6 / 1 x 5 = 18/5

3 3/5 -2 = 1 3/5

Let me know if it's wrong.

Hope this helps

6 0
3 years ago
Please help! Thanks
9966 [12]

Answer:

x = +-sqrt(3) and they are the actual solutions

Step-by-step explanation:

x^2/ (2x-6) = 9/(6x-18)

get a common denominator of 6x-18

x^2/ (2x-6) * 3/3 = 9/(6x-18)

3x^2/ (6x-18) = 9/(6x-18)

since the denominators are the same, the numerators must be the same

3x^2 = 9

divide by 3 on each side

x^2 = 3

take the square root of each side

sqrt(x^2) = +-sqrt(3)

x = +-sqrt(3)



5 0
3 years ago
If anyone knows pls answer<br><br><br>​
svetlana [45]

Answer:

1

Step-by-step explanation:

4 0
3 years ago
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The decimal 1,645.43 rounded to the nearest whole number is​
Margarita [4]

Answer:

1,645

Step-by-step explanation:

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Answer:

Step-by-step explanation:

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5 0
3 years ago
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