A parade traveled 9 miles in 3 hours. How far did the parade travel per minute?
1 answer:
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Answer:
Step-by-step explanation:
Answer:
Step-by-step explanation:
The point P(1,0) and T are on the unit circle C and the arc length from P to T is x.
Let us assume that point P - x i.e. the point obtained by moving clock wise direction along the circle from P is T'.
Because of the symmetry of the circle about the coordinate axes, the x-coordinate of point T' will be and the y-coordinate will be
.
So, coordinates of T' are .
Here we must notice that point T' is the reflection point of T with respect to X-axis. (Answer)
Answer:
m∠EGF = 65° and m∠CGF = 115°
Step-by-step explanation:
Given;
∠EFG = 50°
EF = FG
Solution,
In ΔEFG m∠EFG = 50° and EF = FG.
Since triangle is an isosceles triangle hence their base angles are always equal.
∴
Let the measure of ∠EGF be x.
∴
Now by angle Sum property which states "The sum of all the angles of a triangle is 180°."
m∠EFG + m∠FEG + ∠EGF = 180
Hence
m∠EGF = 65°
Also 'The sum of angles that are formed on a straight line is equal to 180°."
m∠EGF + m∠CGF = 180°
65° + m∠CGF = 180°
m∠CGF = 180° - 65° = 115°
Hence m∠EGF = 65° m∠CGF = 115°