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RideAnS [48]
3 years ago
13

5. How long would it take sound waves traveling through air that is 68°F to travel 2,058 meters? Use an equation to solve the pr

oblem.
Mathematics
1 answer:
svp [43]3 years ago
4 0

Answer:

6 seconds

Step-by-step explanation:

Temperature of air = 68^{\circ}\text{F}

Converting to Celsius

T=(68-32)\dfrac{5}{9}=20^{\circ}\text{C}

Speed of sound in air is given by

v=331.3\sqrt{1+\dfrac{T}{273.15}}\\\Rightarrow v=331.3\sqrt{1+\dfrac{20}{273.15}}\\\Rightarrow v=343.21\ \text{m/s}

d = Distance to travel = 2058 m

Time is given by

t=\dfrac{d}{v}\\\Rightarrow t=\dfrac{2058}{343.21}\\\Rightarrow T=5.99\approx 6\ \text{s}

Time taken to travel 2058 m is 6 seconds.

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Can someone help me with this?
Mandarinka [93]

Answer:

Step-by-step explanation:

Area of rectangle = length * width

                             = (x + 4) (5x)

                             = x *5x + 4 *5x

                            = 5x² + 20x

Perimeter of rectangle = 2*(length + width)

                                     = 2*(x + 4 + 5x)

                                     = 2*(6x + 4)

                                   = 2*6x + 2 *4

                                     = 12x + 8

4 0
3 years ago
A wedding planner purchased both small and large lanterns for a wedding reception. The planner purchased a total of 40 lanterns
Olegator [25]

Answer:

The wedding planner must have purchased 28 small lanterns and 12 large lanterns.

Step-by-step explanation:

8 0
2 years ago
The two largest lizards in the united states are the gila monster and the chuckwalla. The average gila monster is 0.608 meter lo
Mamont248 [21]

Answer:

Gila Monster is 1.54 times that of Chuckwalla.

Step-by-step explanation:

Given:

Average Length of Gila Monster = 0.608 m

Average Length of Chuckwalla = 0.395 m

We need to find the number of times the Gila monster is as the Chuckwalla.

Solution:

Now we know that;

To find the number of times the Gila monster is as the Chuckwalla we will divide the Average Length of Gila Monster by Average Length of Chuckwalla.

framing in equation form we get;

number of times the Gila monster is as the Chuckwalla = \frac{0.608}{0.395} = 1.5392

Rounding to nearest hundredth's we get;

number of times the Gila monster is as the Chuckwalla = 1.54

Hence Gila Monster is 1.54 times that of Chuckwalla.

5 0
3 years ago
please help. will give brainliest! review the table of values for function p(x). what is lim (x -14) p(x), if it exists? (table
Lubov Fominskaja [6]

Answer:

DNE

Step-by-step explanation:

The the given table, we have;

As x approaches -14 from the left, at x = -14.001,  p(x) = 1.96

\lim \limits _{x \to -14^{-}} p(x) = 1.96

As x approaches -14 from the right, at x = -13.999, p(x) = 1.97

\lim \limits _{x \to -14^{+}} p(x) = 1.97

The value of p(x) when x = -14 is \lim \limits _{x \to -14} p(x) = Undefined, or is not definable, therefore, p(x) Does Not Exist (DNE) when x = -14, and we have;

\lim \limits _{x \to -14} p(x)  Does Not Exist, DNE.

3 0
3 years ago
why might you want to use the commutative property to change the order of the intergers in the following sum before adding? -80+
serious [3.7K]
-80+ (-20)+(-173)=-80-20-173=-100-173=-273


6 0
3 years ago
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