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Gemiola [76]
2 years ago
15

Please answer correctly !!!! Will mark brainliest !!!!!!

Mathematics
2 answers:
Vera_Pavlovna [14]2 years ago
8 0

Answer: 6r+16

Step-by-step explanation: All you need to do is to simplify the equation q-10=6(r+1) It becomes q-10=6r+6. You then add 10 on both sides, resulting q=6r+16.

Musya8 [376]2 years ago
3 0

Answer:

h(r) = 6(r+1)+10

Step-by-step explanation:

Just solve for q. Because that's the output. h(r) = q

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To practice for a competition, Carly swam 0.51 kilometer in the pool each day for 3 weeks. How many meters did Carly swim in tho
erica [24]

Answer:

0.51km × 1000 = 510m

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Step-by-step explanation:

first we transform km to m (multiply by 1000)

then we count how much days are in three weeks ( 3 weeks × 7 days)

then we just multiply the meters per day × the days

99% it's true

7 0
3 years ago
Suppose that your business is operating at the 4.5-Sigma quality level. If projects have an average improvement rate of 50% annu
Luda [366]

Answer:

  11.75 years

Step-by-step explanation:

If we ignore the fact that "6-sigma" quality means the error rate corresponds to about -4.5σ (3.4 ppm) and simply go with ...

  P(z ≤ -6) ≈ 9.86588×10^-10

and

  P(z ≤ -4.5) ≈ 3.39767×10^-6

the ratio of these error rates is about 0.000290372. We're multiplying the error rate by 0.5 each year, so we want to find the power of 0.50 that gives this value:

  0.50^t = 0.000290372

  t·log(0.50) = log(0.00290372) . . . . take logarithms

  t = log(0.000290372)/log(0.50) ≈ -3.537045/-0.301030

  t ≈ 11.75

It will take about 11.75 years to achieve Six Sigma quality (0.99 ppb error rate).

_____

<em>Comment on Six Sigma</em>

A 3.4 ppm error rate is customarily associated with "Six Sigma" quality. It assumes that the process may have an offset from the mean of up to 1.5 sigma, so the "six sigma" error rate is P(z ≤ (1.5 -6)) = P(z ≤ -4.5) ≈ 3.4·10^-6.

Using that same criteria for the "4.5-Sigma" quality level, we find that error rate to be P(z ≤ (1.5 -4.5)) = P(z ≤ -3) ≈ 1.35·10^-3.

Then the improvement ratio needs to be only 0.00251699, and it will take only about ...

  t ≈ log(0.00251699)/log(0.5) ≈ 8.6 . . . . years

5 0
3 years ago
Is 2/5 greater than 2/3? ​
liubo4ka [24]

Answer:

no because 2/3 is greater

5 0
2 years ago
Read 2 more answers
Anser true or false:
kakasveta [241]

Answer:

true

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Please please help! DUE MIDNIGHT!!!!!
marysya [2.9K]
We have to convert 2% in to a decimal then multiply it into the x-value which is the months with the addition of 500 because that is the start value.If you were to graph this it would be a linear fuction, y=0.2x+500. The rate of change is found by slope, so rise over run. taking 2 points on the graph and do this
(y 2-y 1)/(x 2-x 1) and graph the equation and get two of the points and find the slope for the rate of change.
3 0
3 years ago
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