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3 years ago

Show that x = -2 is a solution of 3x² + 13x + 14 = 0

Mathematics

1 answer:

Oliga [24]3 years ago

3 0

Answer:

x= -2 is correct answer

Step-by-step explanation:

3(-2×-2)+13(-2)+14=0

3(4)+13(-2)+14=0

12+(-26)+14=0

12-26+14=0

12+14-26=0

26-26=0

0=0

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50 points! What is the value of x? Enter your answer in the box. x =

frosja888 [35]

Answer:

x = 3

Hope this helps!

Step-by-step explanation:

ΔABC is a 45°, 45°, 90° triangle. The longest side ( 6 $\sqrt{2}$ ) can be $x\sqrt{2}$ while AB and CB are x. Because 6 $\sqrt{2}$ is equal to $x\sqrt{2}$ , you can see that x is equal to 6. Both AB and CB are equal to 6. ΔBDC ( CDB ) is a right triangle ( 30°, 60°, 90° ) so, BD = x, CB = 2x, and CD = $x\sqrt{3}$ . CB is equal to 6 so 2x = 6, x = 3.

8 0

7 months ago

??????????????????????

adell [148]

Hello!

You have to find the area of the first rectangle

13 * 25 = 325

Next find the area of the second rectangle

The base is quadripled

13 * 4 = 52

52 * 25 = 1300

Divide the area of rectangle 2 by the area of rectangle 1

1300/ 325 = 4

The answer is D. 4 times bigger

Hope this helps!

5 0

3 years ago

Each of these extreme value problems has a solution with both a maximum value and a minimum value. Use Lagrange multipliers to f

tino4ka555 [31]

Answer:

The minimum value of the given function is f(0) = 0

Step-by-step explanation:

Explanation:-

Extreme value :- f(a, b) is said to be an extreme value of given function 'f' , if it is a maximum or minimum value.

i) the necessary and sufficient condition for f(x) to have a maximum or minimum at given point.

ii) find first derivative $f^{l} (x)$ and equating zero

iii) solve and find 'x' values

iv) Find second derivative $f^{ll}(x) >0$ then find the minimum value at x=a

v) Find second derivative $f^{ll}(x)$ then find the maximum value at x=a

Problem:-

Given function is f(x) = log ( x^2 +1)

step1:- find first derivative $f^{l} (x)$ and equating zero

$f^{l}(x) = \frac{1}{x^2+1} \frac{d}{dx}(x^2+1)$

$f^{l}(x) = \frac{1}{x^2+1} (2x)$ ……………(1)

$f^{l}(x) = \frac{1}{x^2+1} (2x)=0$

the point is x=0

step2:-

Again differentiating with respective to 'x', we get

$f^{ll}(x)=\frac{x^2+1(2)-2x(2x)}{(x^2+1)^2}$

on simplification , we get

$f^{ll}(x) = \frac{-2x^2+2}{(x^2+1)^2}$

put x= 0 we get $f^{ll}(0) = \frac{2}{(1)^2}$ > 0

$f^{ll}(x) >0$ then find the minimum value at x=0

Final answer:-

The minimum value of the given function is f(0) = 0

5 0

3 years ago

Please solve

RoseWind [281]

Answer:

Question 1:

y-2=-3(x+2) - In Point-Slope Form

y=-3x-4 - In Slope-Intercept Form

Question 2:

y-1=1/2(x+6) - In Point-Slope Form

y=1/2x+4 - In Slope-Intercept Form

Step-by-step explanation:

Attached is a picture of the point slope formula which we will be using to write the equations of these lines...

Question 1: Write the equation of the line passing through the points (0, -4) and (-2, 2).

1) First, we need to find the slope, or "m" of this line. Lets plug these two points into slope formula (y2-y1/x2-x1):

(2--4)/(-2-0)

2) Simplify:

6/-2

3) Solve:

m=-3

4) Now, lets plug that slope into point-slope formula along with a set of points that were given to us [I will be using (-2,2)]

y-2=-3(x+2)

5) Now, if you wish to write the equation of the line in slope intercept form, we will have to do some simple algebra. First, distribute -3 to x and 2:

y-2=-3x-6

6) Next, Add 2 to both sides: (Now it is in slope-intercept form)

y=-3x-4

Question 2: Write the equation of the line passing through the points (-6,1) and (-4,2).

1) First, we need to find the slope, or "m" of this line. Lets plug these two points into slope formula (y2-y1/x2-x1):

(2-1)/(-4--6)

2) Simplify:

m=1/2

3) Now, lets plug that slope into point-slope formula along with a set of points that were given to us [I will be using (-6,1)]

y-1=1/2(x+6)

4) Now, if you wish to write the equation of the line in slope intercept form, we will have to do some simple algebra. First, distribute 1/2 to x and 6:

y-1=1/2x+3

5) Next, add 1 to both sides: (Now it is in slope-intercept form)

y=1/2x+4

6 0

3 years ago

Help me please im in a rush

pshichka [43]

Answer: 390 m².

Step-by-step explanation:

$Surface \ area = 11*13+11*12+11*5+2*\frac{12*5}{2}=11*(13+12)+11*5+12*5=\\ =11*25+5*(11+12)=275+5*23=275+115=390\ (m^2).$

7 0

1 year ago

Show that x = -2 is a solution of 3x² + 13x + 14 = 0​

Show that x = -2 is a solution of 3x² + 13x + 14 = 0