Answer:
a) h(x; 7, 5, 12) = (⁵Cₓ)( ⁷C₇₋ₓ) / (¹²C₇)
b) 2.92
Step-by-step explanation:
a)
Here
Number of interviewees = N = 12
Number of job openings = M = 5
Interviews schedules for the first day = n = 7
N − M = 12 - 5 = 7
Using hypergeometric distribution:
Let X be the no. top four candidates interviewed on first day.
The probability mass function of X:
P(X = x) =
/ 
It can be written as:
h(x; n, M, N) =
/
= (5Cx) (7C7-x) / (12C7)
= (⁵Cₓ)( ⁷C₇₋ₓ) / (¹²C₇)
h(x; 7, 5, 12) = (⁵Cₓ)( ⁷C₇₋ₓ) / (¹²C₇)
b)
The expectation is: E(X) = np
E(X) = n * M/N
= 7 * 5/12
= 7 * 0.41667
= 2.9167
Answer:
2/6 so it is a 33% chance
Step-by-step explanation:
because 2/6
so 2 divided by 6 is
0.33333...
move the dot 2 places to the right it would be 33%
2.9 x 10^4 I hope this helps :)
Answer:
2400
Step-by-step explanation:
2244 is the final price. it includes the VAT based on the actual sale price. and that is then actually 15% lower than the originally marked price.
so, let's calculate backwards :
2244 = 100% sale price + 10% VAT = 110%
1% = 2244 / 110 = 20.40
100% (actual sale price) = 20.40×100 = 2040
now, because of the 15% discount, these 2040 are only 85% of the originally marked price.
2040 = 85%
1% = 2040 / 85 = 24.00
100% (the original marked price) = 24×100 = 2400
Answer:
The answer is -3.4. If you have to round it, round it down to 3.
Step-by-step explanation: