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Kaylis [27]
3 years ago
12

2 more after this help

Mathematics
1 answer:
dezoksy [38]3 years ago
5 0

Answer:

y = 1x-5

Step-by-step explanation:

We know two points so we can find the slope

(0,-5) and (5,0)

m = ( y2-y1)/(x2-x1)

   = ( 0 - -5)/(5-0)

   (0+5)/(5-0)

    5/5

=1

We know the y intercept = -5

The slope intercept form is y = mx+b where m is the slope and b is the y intercept

y = 1x-5

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Yuliya22 [10]

Answer:I would add 3x on both sides because it would allow you to have a positive variable saving you time and effort.

Step-by-step explanation:7=7x-9

5 0
3 years ago
Read 2 more answers
Jeff drinks 2/3 of a glass of juice. Write <br> a fraction equivalent to 2/3
Rufina [12.5K]
A fraction that means the same as 2/3 is 4/6.

To find this, you can simply multiple both the numerator and denominator (top and bottom) by any number as long as it's the same number for both top and bottom.
In this case, we used 2 as the number, and multipled it to the top and bottom of 2/3, to get 4/6.

I hope this helps!
7 0
3 years ago
What is the 28th term of the arithmetic sequence with a 1 = 4 and d= -2
Amiraneli [1.4K]

Answer:

Step-by-step explanation:

tn = a + (n-1)*d

t28 = 4 +   (27)*-2     27 because 27 = 28 - 1

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t28 = 4 - 54

t28 = - 50      

4 0
3 years ago
Find the volume of this hexagonal prism.
Arisa [49]
I hope you get it
The answer 2338.2 cm^3

5 0
3 years ago
Which of the following points are more than 5 units from the point P(−2, −2)? Select all that apply. A A (2, 1) B B (4, −1) C C
netineya [11]

The distance between any 2 points P(a,b) and Q(c,d) in the coordinate plane, is given by the formula:<span>

<span> |PQ|= \sqrt{ (a-c)^{2} + (b-d)^{2}}</span></span>


Using this formula we calculate the distances |PA|, |PB|, |PC|, |PD| and |PE| and compare to 5.


|PA|= \sqrt{ (-2-2)^{2} + (-2-1)^{2}}= \sqrt{16+9}= \sqrt{25}=5

|PB|= \sqrt{ (-2-4)^{2} + (-2+1)^{2}}= \sqrt{36+1}= \sqrt{37} \approx 6

|PC|= \sqrt{ (-2-2)^{2} + (-2+3)^{2}}= \sqrt{16+1}= \sqrt{17}\approx4

|PD|= \sqrt{ (-2+6)^{2} + (-2+6)^{2}}= \sqrt{16+16}= \sqrt{32}\ \textgreater \  \sqrt{25}=5

|PE|= \sqrt{ (-2+5)^{2} + (-2-1)^{2}}= \sqrt{9+9}= \sqrt{16}=4


Answer: B and D





3 0
3 years ago
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