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2 years ago

Solve The Equation, Check Your Answer 15=7x+1-5x

2 answers:

5 0

15=7x+1-5x

Put like terms together. ( group anything alike)

15+1=16

7x-5x=2x

16 2x
—- ——-
2x 2x

2x/2x cancels itself out.

16 divided by 2 is 8

x=8

I hope this helped!

LUCKY_DIMON [66]2 years ago

5 0

15=7x+1-5x

Subtract 5x from 7x

15=2x+1

Subtract 1 from 15

14=2x

Divide 2 on both sides

Final Answer: x=7

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Which expression represents the sixth term in the binomial expansion of (5y+3)^10

olga nikolaevna [1]

$\bf \textit{the coefficient and values of an expanded term}\\\\
(5y-3)^{10} \qquad \qquad 
\begin{array}{llll}
expansion\\
for\\
6^{th}~term
\end{array} \quad 
\begin{cases}
\stackrel{term}{k}=0..10\\
\stackrel{exponent}{10}\\
-----\\
k=\stackrel{6^{th}~term}{5}\\
n=10
\end{cases}$

$\bf \stackrel{coefficient}{\left(\frac{n!}{k!(n-k)!}\right)} \qquad \stackrel{\stackrel{first~term}{factor}}{\left( a^{n-k} \right)} \qquad \stackrel{\stackrel{second~term}{factor}}{\left( b^k \right)}$

$\bf \stackrel{coefficient}{\left(\frac{10!}{5!(10-5)!}\right)} \qquad \stackrel{\stackrel{first~term}{factor}}{\left( (5y)^{10-5} \right)} \qquad \stackrel{\stackrel{second~term}{factor}}{\left( (-3)^5 \right)}
\\\\\\
252(5y)^5(-3)^5\implies 252(5^5y^5)(-3)^5\implies -252(3125y^5)(243)
\\\\\\
-191362500y^5$

8 0

3 years ago

What is the prime factorization of 155

xenn [34]

The factors<span> of 155 are 1, 5, 31, and 155, thus </span>the prime factorization should be 5 and 31.

5 0

2 years ago

PLEASE HELP

katrin [286]

Answer:

3 + 4n -9 + 5n

9n - 6

3 0

3 years ago

What is 5.3 x 5.3 x 5.3 x5.3 as a power?

QveST [7]

5.3 to the power of 4

7 0

2 years ago

Two walls have the same area. The first wall is in the shape of a square and has a height

STatiana [176]

Answer:

27 feet

Step-by-step explanation:

Two walls have same area

Area of first wall(square) = 18*18 = 324

Area of second wall = 12 * x = 324

324/12 = 27

27 feet

7 0

2 years ago