<img src="https://tex.z-dn.net/?f=%5Csqrt%20%5Cfrac18" id="TexFormula1" title="\sqrt \frac18" alt="\sqrt \frac18" align="absmidd

Usimov [2.4K]

3 years ago

le" class="latex-formula">

Mathematics

1 answer:

morpeh [17]3 years ago

7 0

Step-by-step explanation:

$\sqrt{1/8}$ = $\sqrt{1} /\sqrt{8}$

$\sqrt{8} =2\sqrt{2}$

$1/(2\sqrt{2} )$

if the denominator is a root then multiply itself by itself to get an integer

$1(2\sqrt{2} )/((2\sqrt{2})(2\sqrt{2} ))$

$\sqrt{2} /4$

Hope that helps :)

You might be interested in

I need help with number 17. <br><br> Please explain your answer.

Phoenix [80]

2*.75= 1.5

2(x+1.1)= 2x+2.2

2x+2.2+1.5

2x+3.7

the answer to the question is e

6 0

3 years ago

The figure shows two semicircles with centers K & M. The semicircles are tangent to each other at point J, and (QN) ⃗ is tan

kodGreya [7K]

Answer: OQ = 34

Step-by-step explanation:

Please find the attached files for the solution

8 0

4 years ago

7(x-8)<br> thanksss please helpp

AlexFokin [52]

The answer is 7x-56.

6 0

3 years ago

pristine printing will print business cards for $0.10 each plus a setup charge of $15 and printing place offers business cards f

Luden [163]

Let's assume

total number of cards =x

Pristine printing business cards:

for $0.10 each plus a setup charge of $15

so, we get equation for cost as

$C=15+0.10x$

Printing Place business cards:

for $0.15 each with a setup charge of $10

so, we get equation for cost as

$C=10+0.15x$

now, we are given

cost from both companies are same

so, we can set costs equal

$15+0.10x=10+0.15x$

now, we can solve for x

$15-10=0.15x-0.10x$

$5 =0.05x$

$x=100$

so,

number of business cards is 100.........Answer

3 0

4 years ago

How can i do this one ☝️

storchak [24]

Hey there!

Let's start by adding 5 to both sides. This eliminates the -5.

1 = r/20

Now to solve for r we can multiply both sides by 20.

20 = r

Check

-4 = 20/20 - 5

-4 = 1 - 5

-4 = -4

Your answer is r = 20.

Hope this helps!

6 0

3 years ago

Read 2 more answers