Question

Q10 Q2.) Find the standard form of the equation of the parabola satisfying the given conditions.

Answer 1

Hello!!

Equation forms:

$y = \frac{x^2}{4} + \frac{x}{2} + \frac{13}{4}$

Therefore, $x^2 - 2x + 4y - 13 = 0$

And, this is how your graph would look

Good luck :)