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gtnhenbr [62]
3 years ago
11

Please find the surface area AND SHOW THE WORK

Mathematics
1 answer:
maria [59]3 years ago
8 0
Area of one triangle:
2x7=84
84/2=42

Area of all the triangles:
42x4=168

Total area:
168+49=217
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|x-5|=3 <br> Whats x? please help?
finlep [7]

Answer:

x = 8 or x = 2

Step-by-step explanation:

We know x - 5 = 3 or x - 5 = -3.

<u>Possibility 1:</u>

Step 1: Add 5 to both sides.

  • x-5+5=3+5
  • x=8

<u>Possibility 2:</u>

Step 1: Add 5 to both sides.

  • x-5+5=-3+5
  • x=2

Step 2: Check if both solutions apply to original equation.

  • |8-5|=3
  • |3|=3
  • 3=3
  • |2-5|=3
  • |-3|=3
  • 3=3

3 0
2 years ago
Read 2 more answers
Solve for x.<br> х°<br> 28°<br> 153°
Allushta [10]

180 - 153 = 27

27 + 28 = 55

x= 180 - 55 = 125

x= 125

4 0
3 years ago
How can i explain "An airplane at can hold 63 passengers is separated into 3 sections. Each section holds the same number of pas
erastovalidia [21]
Idk how to explain but the division sentence should be:
63/3 = 21
7 0
3 years ago
The measures of two complementary angles are
Ede4ka [16]

Answer:

x =17

Step-by-step explanation:

Complementary angles add to 90 degrees

(3x+15) + (2x-10) = 90

Combine like terms

5x +5 = 90

Subtract 90 from each side

5x+5-5= 90-5

5x = 85

Divide each side by 5

5x/5 = 85/5

x =17

8 0
3 years ago
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Please help me answer this question
strojnjashka [21]

Answer:

  • modulus: 3√2
  • argument: -3π/4  (or 5π/4)

Step-by-step explanation:

The modulus is the magnitude of the complex number; the argument is its angle (usually in radians).

__

<h3>rectangular form</h3>

The complex number can be cleared from the denominator by multiplying numerator and denominator by its conjugate:

  \dfrac{-9+3i}{1-2i}=\dfrac{(-9+3i)(1+2i)}{(1-2i)(1+2i)}=\dfrac{-9+3i-18i-6}{1+4}=-3-3i

<h3>polar form</h3>

The magnitude of this number is the root of the sum of the squares of the real and imaginary parts:

  modulus = √((-3)² +(-3)²) = 3√2

The argument is the arctangent of the ratio of the imaginary part to the real part, taking quadrant into consideration.

  arg = arctan(-3/-3) = -3π/4  or  5π/4 . . . . radians

__

  modulus∠argument = (3√2)∠(-3π/4)

3 0
2 years ago
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