Answer:
c. 3.
Explanation:
pOH = -log(1x10^-11)
14-11 = 3 (pOH + pH = 14)
- Hope that helps! Please let me know if you need further explanation.
Answer:
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Explanation:
You need the specif heat capacities of both cobalt and lead.
- Specific heat of cobalt: 0.42 J/g.ºC
- Specific heat of lead: 0.13 J/g.ºC
When the two sheets reach the thermal equilibrium their temperatures are equal.
You can use the equations for the thermal heat to find the equilibrium temperature:
Thermal heat released by the hot sheet, lead:
- Q = 16.6 kg × 0.13J/g.ºC × (63ºC - T)
Thermal heat absorbed by the cold sheet, cobalt:
- Q = 5.78 kg × 0.42J/g.ºC × (T - 11ºC)
Equal the two equations to solve for T:
- 16.6 kg × 0.13J/g.ºC × (63ºC - T) = 5.78kg × 0.42J/g.ºC × (T - 11ºC)
I remove the units for easier handling:
- 135.954 - 2.158T = 2.4276T - 26.7036
Round to 2 significant figures: 35ºC ← answer
Answer:
![\large \boxed{\text{2.5 L}}](https://tex.z-dn.net/?f=%5Clarge%20%5Cboxed%7B%5Ctext%7B2.5%20L%7D%7D)
Explanation:
1. Calculate the moles of NaOH.
2. Calculate the volume of NaOH
![\begin{array}{rcl}\\\text{Molar concentration} &= &\dfrac{\text{moles}}{\text{litres}}\\\\ n &= &\dfrac{c}{V}\\\\\dfrac{\text{0.2 mol}}{\text{1 L}} &=& \dfrac{\text{0.50 mol}}{V}\\\\ \dfrac{0.2V}{\text{1 L}} & = & 0.50\\\\0.2V &= & \text{0.50 L}\\V & = & \dfrac{\text{0.50 L}}{0.2}\\\\& = & \textbf{2.5 L}\\\end{array}\\\text{The volume of the solution is $\large \boxed{\textbf{2.5 L}}$}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Brcl%7D%5C%5C%5Ctext%7BMolar%20concentration%7D%20%26%3D%20%26%5Cdfrac%7B%5Ctext%7Bmoles%7D%7D%7B%5Ctext%7Blitres%7D%7D%5C%5C%5C%5C%20n%20%26%3D%20%26%5Cdfrac%7Bc%7D%7BV%7D%5C%5C%5C%5C%5Cdfrac%7B%5Ctext%7B0.2%20mol%7D%7D%7B%5Ctext%7B1%20L%7D%7D%20%26%3D%26%20%5Cdfrac%7B%5Ctext%7B0.50%20mol%7D%7D%7BV%7D%5C%5C%5C%5C%20%5Cdfrac%7B0.2V%7D%7B%5Ctext%7B1%20L%7D%7D%20%26%20%3D%20%26%200.50%5C%5C%5C%5C0.2V%20%26%3D%20%26%20%5Ctext%7B0.50%20L%7D%5C%5CV%20%26%20%3D%20%26%20%5Cdfrac%7B%5Ctext%7B0.50%20L%7D%7D%7B0.2%7D%5C%5C%5C%5C%26%20%3D%20%26%20%5Ctextbf%7B2.5%20L%7D%5C%5C%5Cend%7Barray%7D%5C%5C%5Ctext%7BThe%20volume%20of%20the%20solution%20is%20%24%5Clarge%20%5Cboxed%7B%5Ctextbf%7B2.5%20L%7D%7D%24%7D)