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Svetllana [295]
4 years ago
6

During a chemical reaction, the amount of energy

Chemistry
1 answer:
brilliants [131]4 years ago
8 0
A: because lets say u have baking soda and vinegar when you mix the they make a gas that can fill a balloon meaning the gas increased so that would mean a solid would decreased
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Que es la tabla periodica, que organiza y para que se utiliza
VladimirAG [237]

Answer:

La tabla periódica, también conocida como la tabla periódica de elementos, es una visualización tabular de los elementos químicos, que están organizados por número atómico, configuración electrónica y propiedades químicas recurrentes. La estructura de la tabla muestra tendencias periódicas.

Explanation:

google definition

3 0
4 years ago
Examples of physical and chemical weathering
lorasvet [3.4K]
Mass is always conserved in a physical change. Energy may be released or absorbed when a substance changes from one physical state to another. In a chemical change, a chemical reaction yields a completely new substance. A substance's particles are changed during a chemical reaction.
5 0
4 years ago
The half-life of cesium-137 is 30 years. Suppose we have a 180 mg sample. Find the mass that remains after t years. Let y(t) be
Stels [109]

Explanation:

1) Initial mass of the Cesium-137=N_o= 180 mg

Mass of Cesium after time t = N

Formula used :

N=N_o\times e^{-\lambda t}\\\\\lambda =\frac{0.693}{t_{\frac{1}{2}}}

Half life of the cesium-137 = t_{1/2}=30 years[p/tex]where,
[tex]N_o = initial mass of isotope

N = mass of the parent isotope left after the time, (t)

t_{\frac{1}{2}} = half life of the isotope

\lambda = rate constant

N=N_o\times e^{-(\frac{0.693}{t_{1/2}})\times t}

Now put all the given values in this formula, we get

N=180mg\times e^{-\frac{0.693}{30 years}\times t}

Mass that remains after t years.

N=180 mg\times e^{0.0231 year^{-1}\times t}

Therefore, the parent isotope remain after one half life will be, 100 grams.

2)

t = 70 years

N_o=180 mg

t_{1/2}= 30 yeras

N=180mg\times e^{-\frac{0.693}{30 years}\times 70 years}

N = 35.73 mg

35.73 mg of cesium-137 will remain after 70 years.

3)

N_o=180 mg

t_{1/2}= 30 yeras

N = 1 mg

t = ?

1 mg =180mg\times e^{-\frac{0.693}{30 years}\times t}

\frac{-30 year}{0.693}\times \ln \frac{1 mg}{180 mg}=t

t = 224.80 years ≈ 225 years

After 225 years only 1 mg of cesium-137 will remain.

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3 years ago
Number the elements sodium, magnesium, and potassium in the predicted order of ionic radius from the largest (1) to the smallest
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Potassium ,sodium, and magnesium
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