Answer:
![\sqrt[5]{13^3} = 13^{\frac{3}{5}}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B13%5E3%7D%20%3D%2013%5E%7B%5Cfrac%7B3%7D%7B5%7D%7D)
Step-by-step explanation:
The values of h and k when f(x) = x^2 + 12x + 6 is in vertex form is -6 and -30
<h3>How to rewrite in vertex form?</h3>
The equation is given as:
f(x) = x^2 + 12x + 6
Rewrite as:
x^2 + 12x + 6 = 0
Subtract 6 from both sides
x^2 + 12x = -6
Take the coefficient of x
k = 12
Divide by 2
k/2 = 6
Square both sides
(k/2)^2 = 36
Add 36 to both sides of x^2 + 12x = -6
x^2 + 12x + 36= -6 + 36
Evaluate the sum
x^2 + 12x + 36= 30
Express as perfect square
(x + 6)^2 = 30
Subtract 30 from both sides
(x + 6)^2 -30 = 0
So, the equation f(x) = x^2 + 12x + 6 becomes
f(x) = (x + 6)^2 -30
A quadratic equation in vertex form is represented as:
f(x) = a(x - h)^2 + k
Where:
Vertex = (h,k)
By comparison, we have:
(h,k) = (-6,-30)
Hence, the values of h and k when f(x) = x^2 + 12x + 6 is in vertex form is -6 and -30
Read more about quadratic functions at:
brainly.com/question/1214333
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The percentage of young adults send between 128 and 158 text messages per day is; 34%
<h3>How to find the percentage from z-score?</h3>
The distribution is approximately Normal, with a mean of 128 messages and a standard deviation of 30 messages.
We are given;
Sample mean; x' = 158
Population mean; μ = 128
standard deviation; σ = 30
We want to find the area under the curve from x = 248 to x = 158.
where x is the number of text messages sent per day.
To find P(158 < x < 248), we will convert the score x = 158 to its corresponding z score as;
z = (x - μ)/σ
z = (158 - 128)/30
z = 30/30
z = 1
This tells us that the score x = 158 is exactly one standard deviation above the mean μ = 128.
From online p-value from z-score calculator, we have;
P-value = 0.34134 = 34%
Approximately 34% of the the population sends between 128 and 158 text messages per day.
Read more about p-value from z-score at; brainly.com/question/25638875
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Answer:
the time percentage is 17%
Step-by-step explanation:
The computation of the time percenatge in the case when the detector lie and done with the mistake is as follows:
L denotes the event in which a person is lying.
NL denotes the event in which a person is not lying.
C denotes the event in which that lie detector works correctly
NC denotes the event in which lie detector is not working correctly
Now
P(C|L) =0.8
And,
P(NC|L) is
=1 - .8
= 0.2
P(C|NL) =0.9
P(NC|NL) is
= 1 -.9
=.1
P(L) = 0.7
P(NL) is
= 1 - .7
= .3
Now
P(NC) =P(NC|L) × P(L) + P(NC|NL) × P(NL)
=. 2 × .7 + .1 ×.3
=. 14+.03
= 0.17
Hence, the time percentage is 17%
Answer:
28
Step-by-step explanation:
The other two angles that are adjacent to the right angle in a right triangle add up to 90. So
