1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
stellarik [79]
3 years ago
5

180% is equivalent to what decimal value

Mathematics
1 answer:
SVETLANKA909090 [29]3 years ago
4 0

Answer:

1.8

Step-by-step explanation:

You might be interested in
How many feet of chain fence are necessary to enclosed a dog pen that is square and has a area of 64 sq feet
Oliga [24]

Answer:

32 feet

Step-by-step explanation:

area of square is given by side^2

Perimeter of  square is given by 4*side

_______________________________

Given

area of square = 64 sq feet

side^2 = 64

side^2 = 8^2

side = 8

thus side = 8 feet

_______________________________________

The dog pen is fenced with chain, hence chain will be fence at the edge of square and at the perimeter.

Thus, length of chain required will be same as the Perimeter of  square.

Perimeter of given dog pen with side length 8 feet = 4*8 = 32 feet.

Thus, 32 feet of chain fence is required.

6 0
3 years ago
Rose bought 5 pencils for $0.69 each, 3 notebooks for $ 2.75 each, and a pocket dictionary for
Marysya12 [62]

Answer: $2.81

Step-by-step explanation:

Pencils: 5 * 0.69 = 3.45

Notebooks: 3 * 2.75 = 8.25
pocket dictionary: 5.49

3.45 + 8.25 + 5.49 = 17.19

20 - 17.19 = 2.81

Therefore, she will get $2.81 change back.

3 0
2 years ago
Read 2 more answers
4> Solve by using Laplace transform: y'+5y'+4y=0; y(0)=3 y'(o)=o
harina [27]

Answer:

y=3e^{-4t}

Step-by-step explanation:

y''+5y'+4y=0

Applying the Laplace transform:

\mathcal{L}[y'']+5\mathcal{L}[y']+4\mathcal{L}[y']=0

With the formulas:

\mathcal{L}[y'']=s^2\mathcal{L}[y]-y(0)s-y'(0)

\mathcal{L}[y']=s\mathcal{L}[y]-y(0)

\mathcal{L}[x]=L

s^2L-3s+5sL-3+4L=0

Solving for L

L(s^2+5s+4)=3s+3

L=\frac{3s+3}{s^2+5s+4}

L=\frac{3(s+1)}{(s+1)(s+4)}

L=\frac3{s+4}

Apply the inverse Laplace transform with this formula:

\mathcal{L}^{-1}[\frac1{s-a}]=e^{at}

y=3\mathcal{L}^{-1}[\frac1{s+4}]=3e^{-4t}

7 0
3 years ago
What’s the answer to f(a)
S_A_V [24]

Answer:

The answer to this is fa

Step-by-step explanation:

This is because you as the solver doesn't know what the variables f or a is so you put them together as multiplication until you do understand what f and a are so you can multiply them.

If you were to graph this it would be a horizontal line going infinite in both directions. That means no slope or y axis.

6 0
3 years ago
Help with me on these plz!!!! :)
Inessa05 [86]

Answer:

_ (repeating)

3. d=3.16

4. v=1.4

5. b=3

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
Other questions:
  • The dance committee has 1036 flowers.They want to divide the flowers evenly among 28 centerpieces.How many flowers will be in ea
    10·2 answers
  • This visual representation shows the sets of real numbers.
    9·1 answer
  • The company you work for has a policy of paying overtime for all hours worked in excess of 40 per week you worked 8 hours each d
    14·1 answer
  • Which of the following could be the equation of the graph shown below? click all that apply.
    10·2 answers
  • An access code consists of of a letter followed by four digits. Any letter can be used, the first digit cannot be 0, and the las
    9·1 answer
  • The perimeter of a rectangle is 30meter. If the length is twice the width, what is the width?
    9·1 answer
  • George wants to buy a shirt that costs $69.00. He has a 20% off coupon. How much will
    6·1 answer
  • One angle of a triangle measures 132°. The other two angles are congruent. Enter and solve an equation to find the measure x of
    6·1 answer
  • How long does it take a snail to travel 10 inches at a rate of .2 inches per minute.
    10·1 answer
  • Anyone wanna t.alk? i am b..ored​
    9·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!