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mote1985 [20]
3 years ago
13

30% of doctors on a hospital are female. if there are 780 doctors altogether, how many doctors are female ? round to the nearest

whole number
Mathematics
2 answers:
Fiesta28 [93]3 years ago
7 0
Percent means per one hundred.

780(30/100)

23400/100

234

So there are 234 female doctors.

Archy [21]3 years ago
4 0
30% as a decimal is 0.3

Multiply 780 by 0.3
780(0.3)=234 female doctors
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asambeis [7]

Answer:

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Step-by-step explanation:

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n\geq (\frac{z\sigma}{ME})^2

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We substitute our given values to calculate the sample size:

n\geq (\frac{z\sigma}{ME})^2\\\\\geq (\frac{1.96\times 12}{5})^2\\\\\geq 22.13\approx23

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3 years ago
Part A
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<u>Given the Parameters</u> :

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Hourly earning = Total earning ÷ number of hours worked

Hourly earning = $238 ÷ 8 = $29.75

B.)

Vacation cost = $1850

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2 years ago
For a-b, reduce to the least non-negative residue
Olenka [21]

Answer:

  a.  6

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Step-by-step explanation:

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  = (4·4·1·3) mod 7 = 48 mod 7 = 6

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b. Powers of 4 mod 11 repeat with period 5:

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3 years ago
I WILL GIVE 20 POINTS TO THOSE WHO ANSWER THIS QUESTION RIGHT NOOOO SCAMS AND EXPLAIN WHY THAT IS THE ANSWER
lubasha [3.4K]

Answer:

<em>13.1</em>  

Step-by-step explanation:

A = bh

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b_{1} = 16 , h_{1} = 9

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11h = 144

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5 0
1 year ago
Forty percent of households say they would feel secure if they had $50,000 in savings. you randomly select 8 households and ask
Kay [80]

Answer:

Let X be the event of feeling secure after saving $50,000,

Given,

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Since, the binomial distribution formula,

P(x=r)=^nC_r p^r q^{n-r}

Where, ^nC_r=\frac{n!}{r!(n-r)!}

If 8 households choose randomly,

That is, n = 8

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=0.12386304

(b) the probability of the number that say they would feel secure is more than five

P(X>5) = P(X=6)+ P(X=7) + P(X=8)

=^8C_6 (0.4)^6 (0.6)^{8-6}+^8C_7 (0.4)^7 (0.6)^{8-7}+^8C_8 (0.4)^8 (0.6)^{8-8}

=28(0.4)^6 (0.6)^2 +8(0.4)^7(0.6)+(0.4)^8

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P(X\leq 5) = P(X=0) + P(X=1) + P(X=2) + P(X=3) + P(X=4) + P(X=5)

=^8C_0 (0.4)^0(0.6)^{8-0}+^8C_1(0.4)^1(0.6)^{8-1}+^8C_2 (0.4)^2 (0.6)^{8-2}+8C_3 (0.4)^3 (0.6)^{8-3}+8C_4 (0.4)^4 (0.6)^{8-4}+8C_5(0.4)^5 (0.6)^{8-5}

=0.6^8+8(0.4)(0.6)^7+28(0.4)^2(0.6)^6+56(0.4)^3(0.6)^5+70(0.4)^4(0.6)^4+56(0.4)^5(0.6)^3

=0.95019264

8 0
3 years ago
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