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julsineya [31]
3 years ago
5

Determine the solution to the system of equations {4x+15y=40

Mathematics
1 answer:
oee [108]3 years ago
8 0

Step-by-step explanation:

4x+15y= 40-5y= 20

= 4x+15y+5y= 40-20

4x+20y= 20

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Tetsuo has 50 arcade tokens . Each arcade game at RetroRamam coast 4 tokens . How many games can Tetsuo play ? (middle school pr
Rufina [12.5K]

Answer:

he can play 12 games

Step-by-step explanation:

but he is gonna have some tokens left over.

8 0
3 years ago
PLEASSE HELP THANK YOU!!!
Inga [223]

Answer:

-3x^4+3x^3+8x^2-2x-5

Step-by-step explanation:

Here we need to move the negative sign to the rest of the variables, and then only add the ones with the same power:

(-2x^4-2x^3+8x^2+2)-(x^4-5x^3+2x+7)\\-2x^4-2x^3+8x^2+2 - x^4+5x^3-2x-7

And then move the variables with the same power closer together

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See how -x^4 and -2x^4 are together?

All we have to do now is combine.

-2x^4-x^4-2x^3+5x^3+8x^2-2x+2-7\\-3x^4+3x^3+8x^2-2x-5

So our answer is -3x^4+3x^3+8x^2-2x-5

3 0
3 years ago
Read 2 more answers
HELP ASAP!! What is the image of (-3,9) after a reflection over the line y=x?
aleksandrvk [35]

Answer:

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8 0
3 years ago
What are the solutions to the quadratic equation x^2-16=0
maks197457 [2]
Good evening.


This is a incomplete quadratic equation, because it does not have the term bx. Therefore, we can solve this faster with the following strategy:

\mathsf{x^2 - 16 = 0}

Add 16 to both sides:

\mathsf{x^2 - 16 + 16 = 0 + 16}\\ \\ \mathsf{x^2 = 16}

Take the square root:

\mathsf{\sqrt {x^2} = \pm\sqrt{16}}\\ \\ \mathsf{\boxed{\mathsf{x = \pm4} }}

Therefore:

\boxed{\boxed{\mathsf{S=\{-4, \ +4\}}}}
4 0
4 years ago
Find x Round your answer to the nearest integer. <br><br> A. 7<br> B. 8<br> C. 6<br> D. 5
Ivenika [448]

Answer:

B

Explanations

in this case the hypotenuse is 10,x is the adjacent side of the angle 37

therefore you have to use cos

cos37=x/10

x=7.9

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I hope this helps

3 0
3 years ago
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