The expression represents the perimeter, in centimeters, of the triangle is 6q - 6r - 5s
<h3>What is the perimeter?</h3>
The formula for perimeter of a triangle is expressed as;
Perimeter = a + b + c
Where a , b and c are the lengths of its side
Now, let's substitute the values
Perimeter = (q + r) + (5q - 10s) + (5s - 7r)
expand the bracket
Perimeter = q + r + 5q - 10s + 5s - 7r
collect like terms
Perimeter = q + 5q + r - 7r -10s + 5s
Add like terms
Perimeter = 6q - 6r - 5s
Thus, the expression represents the perimeter, in centimeters, of the triangle is 6q - 6r - 5s
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Answer:
12
Step-by-step explanation:
you can pack one pack in 20 min
there are three 20 min in one hour
multiply three times the four hours and you get 12
U^2(2u+3)+7(2u+3)
(u^2+7)(2u+3)
Answer:
Total area = 237.09 cm²
Step-by-step explanation:
Given question is incomplete; here is the complete question.
Field book of an agricultural land is given in the figure. It is divided into 4 plots. Plot I is a right triangle, plot II is an equilateral triangle, plot III is a rectangle and plot IV is a trapezium, Find the area of each plot and the total area of the field. ( use √3 =1.73)
From the figure attached,
Area of the right triangle I = 
Area of ΔADC = 
= 
= 
= 
= 
= 30 cm²
Area of equilateral triangle II = 
Area of equilateral triangle II = 
= 
= 73.0925
≈ 73.09 cm²
Area of rectangle III = Length × width
= CF × CD
= 7 × 5
= 35 cm²
Area of trapezium EFGH = 
Since, GH = GJ + JK + KH
17 = 
12 = 
144 = (81 - x²) + (225 - x²) + 2
144 - 306 = -2x² + 
-81 = -x² + 
(x² - 81)² = (81 - x²)(225 - x²)
x⁴ + 6561 - 162x² = 18225 - 306x² + x⁴
144x² - 11664 = 0
x² = 81
x = 9 cm
Now area of plot IV = 
= 99 cm²
Total Area of the land = 30 + 73.09 + 35 + 99
= 237.09 cm²
Answer:
your answer is going to be B: Obtuse