Answer:
4
Step-by-step explanation:
BOOM
Answer:
Your Answer is the second option, could i get brainliest?
Answer:
see attachment
Step-by-step explanation:
We want to sketch the graph of

We want to use tables so we choose some few points and plot.
When x=-6,
y=(-6)²+4(-6)+8=20
When x=-4,
y=(-4)²+4(-4)+8=8
When x=0,
y=(-2)²+4(-2)+8=4
When x=0,
y=(0)²+4(0)+8=8
When x=2,
y=(2)²+4(2)+8=20
The table and graph are shown in attachment.
X²+15x+36<0
at first solve quadratic equation
D=b²-4ac= 225-4*1*36= 81
x=(-b+/-√D)/2a
x=(-15+/-√81)/2= (-15+/-9)/2
x1=(-15-9)/2=-12
x2=(-15+9)/2=-3
we can write x²+15x+36<0 as (x+12)(x+3)<0
(x+12)(x+3)<0 can be 2 cases, because for product to be negative one factor should be negative , and second factor should be positive
1 case) x+12<0, and x+3>0,
x<-12, and x>-3
(-∞, -12) and(-3,∞) gives empty set
or second case) x+12>0 and x+3<0
x>-12 and x<-3
(-12,∞) and (-∞,-3) they are crossing , so (-12, -3) is a solution of this inequality
Answer:
0 is the answer of to question