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3 years ago

Whats the answer for 5x+14=k

Mathematics

2 answers:

Jet001 [13]3 years ago

8 0

= -14/5 + k/5
please give me brainliest.

inn [45]3 years ago

4 0

<span>Simplifying 5x + 14 = k

Reorder the terms: 14 + 5x = k

Solving 14 + 5x = k

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-14' to each side of the equation.

14 + -14 + 5x = -14 + k

Combine like terms: 14 + -14 = 0
0 + 5x = -14 + k
5x = -14 + k

Divide each side by '5'. x = -2.8 + 0.2k

Simplifying x = -2.8 + 0.2k

Hope this helps :)
Brainliest would be great! but its ok if u don't</span>

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kari74 [83]

I actually posted this a while ago and it got answerd by a smart person so here's what I understood

the error is that it assumes that √(x²)=x
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3. Write three ratios equal to 4/36

tia_tia [17]

${\Huge{\boxed{\mathbb{QUESTION}}}$

Write three ratios equal to $\frac{4}{36}$

${\huge{\boxed{\mathbb{EXPLANATION\:WITH\:REASONING\;}}}$

This ratio can be represented as $4:36$

_______________________________

${\Huge{\boxed{\mathbb{THE\:RATIOS}}}$

_______________________________

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_______________________________

${\huge{\boxed{\mathbb{TERMS}}}$

Equivalent/Equal ratios<em> - Definition of Equivalent Ratio A ratio can be represented as a fraction. The concept of an equivalent ratio is similar to the concept of equivalent fractions. A ratio that we get either by multiplying or dividing by the same number, other than zero, to the antecedent and the consequent of a ratio is called an equivalent ratio.</em>

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is 0.75 less or greater than 7 over 8

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3 years ago

Read 2 more answers

[4]

Tanya [424]

Answer:

Angle ACD = 38°

Step-by-step explanation:

The full, correct question is presented the attached image to this solution.

Given

Point O is the centre if the circle

Points A, B, C and D are points on the circle

Angle AOB = 140°

Angle OAC = 14°

Angle AOB = 2 × (Angle ACB) [angle subtended at the centre of the circle is twice the angle subtended at the circumference of the circle)

140° = 2 × (Angle ACB)

Angle ACB = (140°/2) = 70°

(Angle AOB) + (Angle OAB) + (Angle ABO) = 180° [sun of angles in a triangle is 180°]

But Angle OAB = Angle ABO = a [base angles of an iscosceles triangle are equal since OA and OB are both radii for the circle O)

(Angle AOB) + (Angle OAB) + (Angle ABO) = 180°

140° + a + a = 180°

2a = 40°

a = (40/2) = 20°

Angle OAB = Angle ABO = 20°

Angle CAB = (Angle OAC) + (Angle OAB) = 14° + 20° = 34°

Triangle ADC is an iscosceles triangle, hence,

Angle DAC = Angle ACD = x [base angles of an iscosceles triangle are equal]

But

(Angle DCB) + (Angle DAB) = 180° [Opposite angles of a cyclic quadilateral (a quadilateral inscribed in a circle) sum up to give 180°]

Angle DCB = (Angle DCA) + (Angle ACB) = (x + 70°)

Angle DAB = (Angle DAC) + (Angle CAB) = (x + 34°)

(Angle DCB) + (Angle DAB) = 180°

(x + 70°) + (x + 34°) = 180°

2x + 104° = 180°

2x = 180° - 104° = 76°

x = (76°/2) = 38°

Angle DAC = Angle ACD = 38°

Angle ACD = 38°

Hope this Helps!!!

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