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SVEN [57.7K]
2 years ago
9

Please help!! I am literally in tears!!

Mathematics
2 answers:
xz_007 [3.2K]2 years ago
7 0

Answer:

y = -10

Step-by-step explanation:

x = -13 y + 52

y = (x - 52)/-13

~~~~~~~~~~~~~~~~~~

y = (182 - 52)/-13

y = -10

oksano4ka [1.4K]2 years ago
5 0

Answer:

-10

Step-by-step explanation:

Inverse equation: x= -13y +52

simplify: y=-1/-13x + 4

Plug in for x: y= 1/-13 (182) +4

=   -10

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Find the smallest value of k such that the LCM of<br> k and 6 is 60
Advocard [28]

Answer: The smallest valuest value for<em> k </em>is 10, such that LCM o<em>f k</em> and 6 is 60.

Step-by-step explanation:

We know that, LCM = Least common multiple.

For example : LACM of 12 and 60  is 60.

If LCM of k and 6 is 60.

i.e. the least common multiple of k and 6 is 60.

Since, 10 x 6 = 60.

The smallest valuest value for<em> k </em>should be 10, such that LCM o<em>f k</em> and 6 is 60.

Hence, the smallest value of k is 10.

5 0
3 years ago
spaceship earth at epcot center in florida is a 180 ft geosphere. estimate its volume by assuming it is a sphere with a diameter
rjkz [21]
Volume of a sphere:
V = 4/3 · r³ π
Diameter: d = 180 ft, r = d/2, r = 90 ft
V = 4/3 · 90³ · 3.14
V = 4/3 · 729,000 · 3.14
V = 3,052,080 ft³
4 0
3 years ago
Nemecek Brothers make a single product on two separate production lines, A and B. Its labor force is equivalent to 1000 hours pe
frez [133]

Answer:

(a) The inequality for the number of items, x, produced by the labor, is given as follows;

250 ≤ x ≤ 600

(b) The inequality for the cost, C is $1,000 ≤ C ≤ $3,000

Step-by-step explanation:

The total time available for production = 1000 hours per week

The time it takes to produce an item on line A = 1 hour

The time it takes to produce an item on line B = 4 hour

Therefore, with both lines working simultaneously, the time it takes to produce 5 items = 4 hours

The number of items produced per the weekly labor = 1000/4 × 5 = 1,250 items

The minimum number of items that can be produced is when only line B is working which produces 1 item per 4 hours, with the weekly number of items = 1000/4 × 1 = 250 items

Therefore, the number of items, x, produced per week with the available labor is given as follows;

250 ≤ x ≤ 1250

Which is revised to 250 ≤ x ≤ 600 as shown in the following answer

(b) The cost of producing a single item on line A = $5

The cost of producing a single item on line B = $4

The total available amount for operating cost = $3,000

Therefore, given that we can have either one item each from lines A and B with a total possible item

When the minimum number of possible items is produced by line B, we have;

Cost = 250 × 4 = $1,000

When the maximum number of items possible, 1,250, is produced, whereby we have 250 items produced from line B and 1,000 items produced from line A, the total cost becomes;

Total cost = 250 × 4 + 1000 × 5 = 6,000

Whereby available weekly outlay = $3000, the maximum that can be produced from line A alone is therefore;

$3,000/$5 = 600 items = The maximum number of items that can be produced

The inequality for the cost, C, becomes;

$1,000 ≤ C ≤ $3,000

The time to produce the maximum 600 items on line A alone is given as follows;

1 hour/item × 600 items = 600 hours

The inequality for the number of items, x, produced by the labor, is therefore, given as follows;

250 ≤ x ≤ 600

8 0
3 years ago
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lions [1.4K]
Hello!

To be perpendicular to x = 4, the line must be y = something. This eliminates answer choices #2 and #4. Also, to pass through the point (.5, 7), the line must be y = 7.

So answer choice #3.

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8 0
3 years ago
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Crazy boy [7]
Tanya played 15 rounds.
375-75=300
30-10=20
300÷20=15
8 0
3 years ago
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