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2 years ago

Please help!! I am literally in tears!!

Mathematics

2 answers:

xz_007 [3.2K]2 years ago

7 0

Answer:

y = -10

Step-by-step explanation:

x = -13 y + 52

y = (x - 52)/-13

~~~~~~~~~~~~~~~~~~

y = (182 - 52)/-13

y = -10

oksano4ka [1.4K]2 years ago

5 0

Answer:

-10

Step-by-step explanation:

Inverse equation: x= -13y +52

simplify: y=-1/-13x + 4

Plug in for x: y= 1/-13 (182) +4

= -10

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Solve, 3x+18>7, is the question

Lelu [443]

Answer:

I hope this helps

Step-by-step explanation:

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3 0

1 year ago

on dividing $200 between A and B such that twice of A's share is less than 3 times than B's share by $20

Wittaler [7]

Answer:

Share of A is $116 and Share of B is $84.

Step-by-step explanation:

Let the share of A be $x$

Let the share of B be $y$

Given:

$200 is shared between A and B

So, $x+y =\$200\ \ \ \ equation \ 1$

Also given;

twice of A's share is less than 3 times than B's share by $20

$2x= 3y -20\\2x-3y = -20 \ \ \ \ equation \ 2$

Solution:

Now multiplying equation 1 by 3 we get,

$3x+3y=600 \ \ \ \ equation \ 3$

Now Adding equation 2 and equation 3 we get

$(2x-3y = -20)+ (3x+3y=600)\\5x=580\\\\x=\frac{580}{5}=\$116$

Now Substituting the value of x in equation 1 we get,

$x+y=200\\116+y=200\\y=200-116 = \$84$

Hence, Share of A is $116 and Share of B is $84.

8 0

3 years ago

The radius is 7 3

Verizon [17]

If the radius is 7 and 3/4, then the answer is 48.6947
c=2pie•r
plug in 7 and 3/4 for r and get 48.6947

3 0

3 years ago

Let T:ℝ2→ℝ2 be the linear transformation that first rotates points clockwise through 45∘ (????/4 radians) and then reflects poin

Alisiya [41]

Answer:

$T = \left[\begin{array}{ccc}-\frac{1}{\sqrt{2} } &\frac{1}{\sqrt{2} }\\\frac{1}{\sqrt{2} }&\frac{1}{\sqrt{2} }\end{array}\right]$

Step-by-step explanation:

Let General Transformation matrix be denoted as T

Step 1: Clockwise rotation of 45 degrees

General counterclockwise rotation matrix in 2-dimension is given as

$R(\theta)=\left[\begin{array}{ccc}cos\theta & - sin\theta\\sin\theta&cos\theta\\\end{array}\right]$

For clockwise rotation we need to insert θ as negative in the above matrix. Therefore, the resulting matrix is

$R(-\theta)=\left[\begin{array}{ccc}cos\theta & sin\theta\\-sin\theta&cos\theta\\\end{array}\right]$

as sin(-θ) = -sin (θ) and cos(-θ) = cos (θ)

For 45 degrees

$sin(45) = \frac{1}{\sqrt{2} }$ and $cos(45) = \frac{1}{\sqrt{2} }$

$R(-45)=\left[\begin{array}{ccc}\frac{1}{\sqrt{2} } & \frac{1}{\sqrt{2} }\\-\frac{1}{\sqrt{2} }&\frac{1}{\sqrt{2} }\\\end{array}\right]$

Step 2: Reflection through line y = x

This type of reflection maps (x,y)→(y,x)

Therefore the general matrix is

$R(x,y)=\left[\begin{array}{ccc}0&1\\1&0\end{array}\right]$

Step 3: General Transformation Matrix

T = R(x,y) R(-θ)

$T=\left[\begin{array}{ccc}0&1\\1&0\end{array}\right] \left[\begin{array}{ccc}\frac{1}{\sqrt{2} } & \frac{1}{\sqrt{2} }\\-\frac{1}{\sqrt{2} }&\frac{1}{\sqrt{2} }\\\end{array}\right]$

$T = \left[\begin{array}{ccc}-\frac{1}{\sqrt{2} } &\frac{1}{\sqrt{2} }\\\frac{1}{\sqrt{2} }&\frac{1}{\sqrt{2} }\end{array}\right]$

3 0

2 years ago

One side of a triangular lot is 150 ft and the angel oppiste this side is 55 degrees. Another angel is 63 degrees. Determine how

Olenka [21]

Answer:

474.84 ft of fencing is needed

Step-by-step explanation:

We know that the angles of a triangle sum up 180º. We already know 2 of the triangle's angles (55º and 63º). Therefore the third angle measures:

180 - 55 - 63 = 62.

To know how much fencing is needed, we need the perimeter of the triangle, so we need to find out how much the other sides of the lot measure.

We will use law of sins to solve this problem.

First we solve for y:

$\frac{150}{sin55}= \frac{y}{sin63} \\y=150 (sin63)/(sin55)\\y=133.65/.8191\\y=163.16$

Now we solve for the other side of the lot, x:

$\frac{150}{sin55}=\frac{x}{sin62}\\ x=150(sin62)/(sin55)\\x=150(.8829)/.8191\\x=132.435/.8191\\x=161.68$

Now that we have the measures of all the sides we sum them up

total fencing needed= 150 + 163.16 + 161.68 = 474.84

5 0

2 years ago