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jeka57 [31]
3 years ago
15

Find a slope thatgoes through the points(2,6) and (1,8)​

Mathematics
1 answer:
marusya05 [52]3 years ago
6 0

Answer:

The slope is -2.

Step-by-step explanation:

m=(y2-y1)/(x2-x1)=(8-6)/(1-2)=2/-1=-2

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2. The line that passes through the points (-6, p)
Kobotan [32]
Answer: -26=p


Explanation: The slope formula is m=(y2-y1)/(x2-x1).

Thus, we have 6=(2-p)/(-10-(-6)).

Combining the xs gives us 6=(2-p)/-4.

Multiplying both sides by -4 leaves us with -24=2-p.

We do -24-2 to isolate p and find that p=-26.
5 0
2 years ago
Raina drove 936 miles in 13 hours.
valentinak56 [21]

Answer:

8 hours

Step-by-step explanation:

72 miles per hour

576/72= 8

3 0
3 years ago
Read 2 more answers
Secants BE and CF intersect at point D inside A. What is the measure of CDE?
Aleks04 [339]
MCE = 360 - (150 + 70 + 50)
mCE = 360 - 270
mCE = 90

<CDE = 1/2(mBE + mCE)
<CDE = 1/2(150 + 90)
<CDE = 1/2(240)
<CDE = 120

answer
<CDE = 120°
6 0
3 years ago
Which ordered pair describes the location of point A? (-6, 5) (-6, -5) (5, -6) (5, 6)
Neko [114]

Answer:

the answer is -6,5

Step-by-step explanation:

just look at the left side ( the x axis )first then right(the y axis)

8 0
3 years ago
Simplify the expression by using a double-angle formula. 2 sin 31°cos 31°
qwelly [4]

The double angle formula for the sine is

\sin(2x) = 2\sin(x)\cos(x)

The right hand side is exactly your expression, where x = 31^\circ

So, rewriting the expression from right to left, we have

2\sin(31^\circ)\cos(31^\circ) = \sin(2\cdot 31^\circ) = \sin(61^\circ)

6 0
2 years ago
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