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Anarel [89]
3 years ago
9

Joe's final exam has true/false questions, worth 2 points each, and multiple choice questions, worth 5 points each. Let x be the

number of true/false
he gets correct, and let y be the number of multiple choice questions he gets correct.
He needs more than 90 points on the exam to get an A in the class. Using the values and variables given, write an inequality describing this.
Mathematics
1 answer:
mixer [17]3 years ago
7 0

This is the inequality

2x + 5y ≥ 90

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<img src="https://tex.z-dn.net/?f=5x%2B7x-1%2F2x%2B1%2F4%3D6%5C%5Cx%3D%3F" id="TexFormula1" title="5x+7x-1/2x+1/4=6\\x=?" alt="5
fredd [130]

Answer:

Step-by-step explanation:

5x + 7x - 1/2x + 1/4 = 6

move x to one side move numbers to the other side

5x + 7x - 1/2 x = 6 - 1/4

add x and numbers

23/2x = 23/4

divide both side by 23/2

x = (23/4)/(23/2)

  = 1/2

plug it in to check the answer

5/2 + 7/2 - 1/4 + 1/4 = 6

12/2 = 6

6 0
3 years ago
I JUST NEED 2. ANSWERED! THIS IS DUE! Solve for x
8_murik_8 [283]

Answer:

x=24

Step-by-step explanation:

Since line A and B are parallel, 3x+7 is equivalent to Angle 6 as they are corresponding angles.

We also know that 4x+5+Angle 6 = 180 as they are a linear pair. We can use substitution and substitute 3x+7 for Angle 6...

4x+5+3x+7=180

7x+12=180

7x=168

x=24

7 0
2 years ago
Read 2 more answers
The length of the hypotenuse of a right angled triangle exceeds the length of the base by 2cm and exceeds twice the length of th
insens350 [35]

Answer: a = 8;  b = 15;  c = 17

Step-by-step explanation:

c = b + 2  and c = 2a + 1

b = c − 2 and a =  \frac{c-1}{2}

​

c² = b² + a²  

c^{2} = (c-2)^{2} + \frac{c-1}{2}\\

c^{2}= \frac{4 (c-2)^{2}+(c - 1)^{2}  }{4}

4c^{2}={4 (c^{2} + 4 -4c)+c ^{2}  + 1-2c

4c^{2}={4 c^{2} + 16 -16c)+c ^{2}  + 1-2c

c^{2}-18c+17=0

c(c -17)-1(c-17)=0

​(c -1)(c-17)=0

c = 1 or c = 17

If c = 1 then b = 1 - 2 = -1, that's not possible

So x = 17

b = 17 - 2 = 15

a = \frac{17-1}{2}  = 8

Length sides of the triangle are 17 cm, 15 cm and 8 cm.

I saw some of this on a site but I want to make sure its correct so we're gonna apply the pythagorean theory and see if its correct.

a^{2} + b^{2} = c^{2} \\8^{2} + 15^{2} = 17^{2} \\64 + 225 = 289\\289 = 289\\

This shows that this is correct.

Hope this helped! Again, some of this was from a site, not from me.

3 0
3 years ago
BRAINLIEST !!! Can someone add me as a friend plz need to look someone up but cant till someone adds me
eimsori [14]

Answer:

I have done what you want

4 0
2 years ago
Read 2 more answers
Simplify 4 to the 7th over 5 squared all raised to the 3rd power.
Radda [10]
First write out your original equation.
{(\frac{ {4}^{7} }{ {5}^{2} } ) }^{3}
Then use the law of exponents(power of a power) to simplify.
\frac{ {4}^{21} }{ {5}^{6} }
(Multiply the numerator and denominator exponents by the outside power.)

The answer is 4 to the 21st over 5 to the 6th.
6 0
3 years ago
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