Answer:
1. i Sampling bias and
ii. Question order bias
2. Non response Bias
3.i. sampling bias
ii.question order bias
4. i. response bias
ii.sampling bias
Step-by-step explanation:
we have basically four types of bias in a research which are;
1. Sampling bias
2. Response bias
3. Non response bias
4. Question order bias
Answer:
y = -4/3x +4
Step-by-step explanation:
y= mx+b
solve for y.
4x+3y=12
Step 1: Add -4x to both sides.
4x+3y+−4x=12+−4x
3y=−4x+12
Step 2: Divide both sides by 3.
Let's solve for y.
4x+3y=12
Step 1: Add -4x to both sides.
4x+3y+−4x=12+−4x
3y=−4x+12
Step 2: Divide both sides by 3.
3y / 3 =-4x +12 /3
y = -4/3x +4
hopes this helps you out
The missing values represented by x and y are 8 and 20, that is
(x, y) = (8, 20)
The function y = 16 + 0.5x is a linear equation that can be solved graphically. This means the values of both variables x and y can be found on different points along the straight-line graph.
The ordered pairs simply mean for every value of x, there is a corresponding value of y.
The 2-column table has values for x and y which all satisfy the equation y = 16 + 0.5x. Taking the first row, for example, the pair is given as (-4, 14).
This means when x equals negative 4, y equals 14.
Where y = 16 + 0.5x
y = 16 + 0.5(-4)
y = 16 + (-2)
y = 16 - 2
y = 14
Therefore the first pair, just like the other four pairs all satisfy the equation.
Hence, looking at the options given, we can determine which satisfies the equation
(option 1) When x = 0
y = 16 + 0.5(0)
y = 16 + 0
y = 16
(0, 16)
(option 2) When x = 5
y = 16 + 0.5(5)
y = 16 + 2.5
y = 18.5
(5, 18.5)
(option 3) When x = 8
y = 16 + 0.5(8)
y = 16 + 4
y = 20
(8, 20)
From our calculations, the third option (8, 20) is the correct ordered pair that would fill in the missing values x and y.
To learn more about the straight line visit:
brainly.com/question/1852598
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0.004 is one tenth of 0.04 or 0.04 is ten times 0.004
<span>9,500,000 is the next number in the pattern. Each time you multiply the number on the left by 100 to get the number on the right.</span>
